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Two particles are placed at some distance. If mass of each of the two particles is doubled, keeping the distance between them unchanged, the value of gravitational force between them will become/remain
- a)1/4 times
- b)4 times
- c)1/2 times
- d)unchanged
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
Two particles are placed at some distance. If mass of each of the two ...
Explanation:
When two particles are placed at some distance, the gravitational force between them is given by the formula:
F = G(m1m2)/r^2
Where,
F = gravitational force
G = gravitational constant
m1 = mass of particle 1
m2 = mass of particle 2
r = distance between the particles
Now, if the mass of each of the two particles is doubled, then the new gravitational force between them will be:
F' = G(2m1)(2m2)/r^2
F' = 4G(m1m2)/r^2
F' = 4F
Therefore, the value of gravitational force between them will become 4 times the original value. Hence, option B is the correct answer.
Key Points:
- Gravitational force between two particles is given by F = G(m1m2)/r^2
- If the mass of each particle is doubled, then the new gravitational force is 4 times the original force.
When two particles are placed at some distance, the gravitational force between them is given by the formula:
F = G(m1m2)/r^2
Where,
F = gravitational force
G = gravitational constant
m1 = mass of particle 1
m2 = mass of particle 2
r = distance between the particles
Now, if the mass of each of the two particles is doubled, then the new gravitational force between them will be:
F' = G(2m1)(2m2)/r^2
F' = 4G(m1m2)/r^2
F' = 4F
Therefore, the value of gravitational force between them will become 4 times the original value. Hence, option B is the correct answer.
Key Points:
- Gravitational force between two particles is given by F = G(m1m2)/r^2
- If the mass of each particle is doubled, then the new gravitational force is 4 times the original force.
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Two particles are placed at some distance. If mass of each of the two particles is doubled, keeping the distance between them unchanged, the value of gravitational force between them will become/remaina)1/4 timesb)4 timesc)1/2 timesd)unchangedCorrect answer is option 'B'. Can you explain this answer?
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