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The equation = 4 cos (π/2 (x2  + 2x)) has how many distinct real solutions for x ≥  0
    Correct answer is '1'. Can you explain this answer?
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    The equation = 4 cos (π/2 (x2 + 2x))has how many distinct real solu...
    If x ≥ 0 it implies that x+2 is also always positive.
    The minimum value the LHS will be
    thus x = 0 as we are given that x ≥ 0
    The RHS has a cos term and the maximum value of RHS is 4 when the 
    It is possible when cos 
    or x2 + 2x = 4n
    Thus there are many solutions for the equation but LHS achieves the value only once when x = 0. There is one solution possible.
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    The equation = 4 cos (π/2 (x2 + 2x))has how many distinct real solutions for x ≥ 0Correct answer is '1'. Can you explain this answer?
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