A muff coupling is connecting two shaft the torque involved is 650 n-m...
Solution:
Given data:
Torque, T = 650 N-m
Shaft diameter, d = 45 mm
Length of the key, l = 14 mm
Height of the key, h = 80 mm
We know that the shear stress induced in the key can be calculated using the formula:
τ = T/(2*π*r*l)
where, r = d/2
Calculating radius(r):
r = d/2 = 45/2 = 22.5 mm
Calculating shear stress(τ):
τ = T/(2*π*r*l)
τ = 650/(2*π*22.5*14) = 0.675 N/mm²
Therefore, the shear stress induced in the key is 0.675 N/mm².
Explanation:
A muff coupling is used for connecting two shafts. It consists of two halves that are bolted together. The torque is transmitted from one shaft to another through the coupling. A key is used to prevent relative rotation between the shaft and the coupling.
The shear stress induced in the key can be calculated using the formula τ = T/(2*π*r*l), where T is the torque, r is the radius of the shaft, and l is the length of the key. The shear stress is the force acting parallel to the cross-sectional area of the key.
In this problem, we are given the torque, shaft diameter, and length and height of the key. We can calculate the radius of the shaft by dividing the diameter by 2. Then, we can use the formula to calculate the shear stress induced in the key.
The shear stress induced in the key is an important parameter in the design of the muff coupling. The key should be designed to withstand the maximum shear stress induced by the torque. If the shear stress exceeds the yield strength of the material, the key may fail, leading to the failure of the muff coupling.
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