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 When all classes have equal width, the heights of the rectangles in Histogram will be numerically equal to the
  • a)
    Class frequencies
  • b)
    Class boundaries
  • c)
    Both
  • d)
    None
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
When all classes have equal width, the heights of the rectangles in Hi...
Explanation:

In a histogram, the width of each class interval represents the range of values that fall within that interval. When all classes have equal width, it means that the range of values represented by each class is the same.

The height of each rectangle in a histogram represents the frequency or count of values that fall within the corresponding class interval. Therefore, when all classes have equal width, the height of each rectangle will be numerically equal to the class frequencies.

Let's consider an example to illustrate this:

Suppose we have a dataset of exam scores and we want to create a histogram to visualize the distribution of scores. We divide the scores into class intervals of equal width, such as 60-69, 70-79, 80-89, and so on.

If there are 20 scores in the 60-69 interval, 30 scores in the 70-79 interval, and 25 scores in the 80-89 interval, the height of the rectangles representing these intervals will be numerically equal to the class frequencies.

So, in this example, the height of the rectangle for the 60-69 interval will be 20, the height of the rectangle for the 70-79 interval will be 30, and the height of the rectangle for the 80-89 interval will be 25.

Therefore, when all classes have equal width, the heights of the rectangles in a histogram will be numerically equal to the class frequencies. This is because the width of the rectangles represents the range of values in each class, and the height represents the frequency or count of values in each class.
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When all classes have equal width, the heights of the rectangles in Histogram will be numerically equal to thea)Class frequenciesb)Class boundariesc)Bothd)NoneCorrect answer is option 'A'. Can you explain this answer?
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