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If x3 + 2x2−Ax has only one of its three real and unequal roots between [-1,3). Then the value of A can lie between?
  • a)
    A ∈ (−∞ , −1) U (15, ∞ )
  • b)
    A ∈ (−∞ ,−1] U [15, ∞ )
  • c)
    A ∈ [15, ∞ )
  • d)
    A ∈ [−1, ∞ )
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
If x3 + 2x2−Axhas only one of its three real and unequal roots b...
The given equation can be written as (x2 + 2x − A) = 0
=> x = 0 is one such root which lie between 3 and -1.
=> x2 + 2x − A = 0 must not have a single root between 3 and -1 => f(3)*f(-1) > 0
=> (15-A) (-1-A) > 0
=> (A-15)(A+1) > 0
=> A ∈ (−∞ ,−1) U (15, ∞ )
But the given equation x(x+ 2x−A) = 0 has unequal roots => x2 + 2x−A = 0 must have real and unequal roots => 4 + 4A > 0 => A > -1.  
=> A ∈ [15,∞ )
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If x3 + 2x2−Axhas only one of its three real and unequal roots between [-1,3). Then the value of A can lie between?a)A∈(−∞, −1)U(15,∞)b)A∈(−∞,−1]U[15,∞)c)A ∈[15, ∞)d)A ∈[−1, ∞)Correct answer is option 'C'. Can you explain this answer?
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