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Find the length of a diagonal of a rectangle whose perimeter is 28 cm and breadth is 6 cm.?
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Find the length of a diagonal of a rectangle whose perimeter is 28 cm ...
The perimeter of a rectangle is the sum of all four sides. The formula for the perimeter of a rectangle is P = 2L + 2W, where L is the length of the rectangle and W is the width or breadth of the rectangle.
So, 28 cm = 2L + 2W.
Given breadth is 6cm.
so,
28 cm = 2L + 2(6 cm)
28 cm = 2L + 12 cm
Now, we know that L + W = (28-12)/2 = 8cm.
The diagonal of a rectangle is the hypotenuse of the right angle triangle formed by its length and breadth.
The length of the diagonal of a rectangle can be found by using the Pythagorean theorem which states that the square of the hypotenuse of a right-angled triangle is equal to the sum of the squares of the other two sides. The formula for the diagonal of a rectangle is d = √(L^2 + W^2).
So, d = √(L^2 + W^2) = √(8^2 + 6^2) = √(64 + 36) = √(100) = 10 cm
Therefore, the length of the diagonal of a rectangle whose perimeter is 28 cm and breadth is 6 cm is 10 cm.
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