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If 3 ^ a = 5 ^ b = (75) ^ c then the value of ab - c(2a b) reduces to?
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If 3 ^ a = 5 ^ b = (75) ^ c then the value of ab - c(2a b) reduces t...
Solution:

Given, 3^a = 5^b = (75)^c

We know that 75 = 3^1 × 5^2

∴ (75)^c = (3^1 × 5^2)^c = 3^c × 5^(2c)

So, we can write 3^a = 5^b = 3^c × 5^(2c)

Let us take two cases:

Case I: When a = b

If a = b, then 3^a = 5^b

∴ 3^a = 3^c × 5^(2c) and 5^b = 3^c × 5^(2c)

∴ 3^a = 5^b

⇒ 3^a/5^b = 1

⇒ 3^(a-b) = 1

⇒ a - b = 0

Now, ab - c(2a - b) = ab - 2ac + bc

⇒ b(a - 2c) + ac

⇒ b(a - 2c) + b(a - b)

⇒ b(a - b - 2c)

Since a = b, the above expression becomes:

⇒ b(a - a - 2c) = -2bc

Therefore, ab - c(2a - b) reduces to -2bc.

Case II: When a ≠ b

If a ≠ b, then 3^a ≠ 5^b

Let m = a - b

Then 3^m = 5^m × k (where k is some constant)

Since 3 and 5 are prime numbers, m must be 0

Thus, a = b

Now, using the same method as in Case I, we get:

ab - c(2a - b) = -2bc

Therefore, the value of ab - c(2a - b) reduces to -2bc, irrespective of whether a = b or not.
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If 3 ^ a = 5 ^ b = (75) ^ c then the value of ab - c(2a b) reduces t...
If 3 ^ a = 5 ^ b = (75) ^ c then the value of ab - c(2a b) reduces to?
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If 3 ^ a = 5 ^ b = (75) ^ c then the value of ab - c(2a b) reduces to?
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