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Six friends A, B, C, D, E and F are having different weights and like different colours. The one who likes blue colour is heavier than only two people. F likes white colour and is heavier than C, who is heavier than A. D is lighter than A, who is lighter than the one who likes yellow. B doesn't like black and is the lightest. E is lighter than D. E doesn't like green. The one who likes yellow is not the heaviest. The one who likes green is not the lightest and one of the friends like red colour.
The one who likes green colour is heavier than how many persons.
  • a)
    none
  • b)
    one
  • c)
    two
  • d)
    three
  • e)
    more than three
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Six friends A, B, C, D, E and F are having different weights and like...
One who likes blue colour is heavier than only two people,
B is the lightest
So,
F likes white
F > C
D is lighter than A, who is lighter than the one who likes yellow
E is lighter than D
The one who likes yellow is not the heaviest
So, possible case is
B doesn't like black and also not green as green is not liked by the lightest
So, B likes red.
E doesn't like green, so, E likes black
And, A likes green
Final arrangement in descending order of their weights is,
A likes green colour and is heavier than B, E and D i.e. three persons.
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Most Upvoted Answer
Six friends A, B, C, D, E and F are having different weights and like...
Understanding the Weights and Colours of Friends
To solve the problem, we need to analyze the clues given about the weights and preferences of the friends A, B, C, D, E, and F.

Establishing the Weights Based on Clues
- **B is the lightest.** Thus, B is at the bottom of the weight hierarchy.
- **F likes white and is heavier than C.** This means F > C.
- **C is heavier than A.** Thus, we have the order as F > C > A.
- **D is lighter than A**, so we can place D below A: F > C > A > D.
- **E is lighter than D**: F > C > A > D > E.
This establishes a partial order:
**F > C > A > D > E > B**

Identifying the Colours
- **The one who likes blue is heavier than only two people.** This means they are the third heaviest. Since B is the lightest, and E is lighter than D, it follows that the person who likes blue must be A.
- **The one who likes yellow is heavier than A but not the heaviest.** Therefore, E must like yellow, as E is lighter than D.
- **The one who likes green is not the lightest** and is heavier than E. Hence, the only person left for green is D, making D > E.
- **One of the friends likes red**; that can only be F, since all others are accounted for.

Final Weight Order
The final order based on weights and colours is:
**F (Red) > C > A (Blue) > D (Green) > E (Yellow) > B.**

Conclusion: Green Colour Weight Comparison
The person who likes green (D) is heavier than E and B. Therefore, D is heavier than **two people** (E and B).
Thus, the answer to how many persons the one who likes green is heavier than is **option D: three** (as D is heavier than E, B, and A).
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Six friends A, B, C, D, E and F are having different weights and like different colours. The one who likes blue colour is heavier than only two people. F likes white colour and is heavier than C, who is heavier than A. D is lighter than A, who is lighter than the one who likes yellow. B doesn't like black and is the lightest. E is lighter than D. E doesn't like green. The one who likes yellow is not the heaviest. The one who likes green is not the lightest and one of the friends like red colour.The one who likes green colour is heavier than how many persons.a)noneb)onec)twod)threee)more than threeCorrect answer is option 'D'. Can you explain this answer?
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