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Consider a circuit shown below:
If the cut-in voltage of all the diodes equal to 0.7 V on their ON-state, then the value of current ‘I’ is equal to
  • a)
    0.86 mA
  • b)
    1.86 mA
  • c)
    0 mA
  • d)
    1.72 mA
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Consider a circuit shown below:If the cut-in voltage of all the diode...
V1=−0.7+0.7=0V
I=I0−I1=−0.86mA
I2=−0.7+55kΩ=0.86mA
I3=I2−I=0.86+0.86=1.72mA
I1>0A⇒D1 is forward Bias
I3>0A⇒D3 is forward Bias I>0A⇒D2 is forward Bias.
So, our assumption regarding D3 is wrong and it will be Reverse Bias.
As D2 is Reverse Bias, I=0 mA.
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Consider a circuit shown below:If the cut-in voltage of all the diodes equal to 0.7 V on their ON-state, then the value of current ‘I’ is equal toa)0.86 mAb)1.86 mAc)0 mAd)1.72 mACorrect answer is option 'C'. Can you explain this answer?
Question Description
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