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The results of two plate load tests performed on a given location with two circular plates are given below:1. Diameter = 750 mm, S = 15 mm, Q = 150 kN2. Diameter = 300 mm, S = 15 mm, Q = 50 kNUse Housel’s equation i.e. Q = Aq + PsA = contact areaq = bearing pressure beneath area A (constant)P = perimeter of footings = Perimeter shear (constant)Determine the load (in kN) on circular footing 1.2 m diameter that will cause a settlement of 15 mm.a)279.6b)402.18c)512.2d)558.8Correct answer is option 'A'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared
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the GATE exam syllabus. Information about The results of two plate load tests performed on a given location with two circular plates are given below:1. Diameter = 750 mm, S = 15 mm, Q = 150 kN2. Diameter = 300 mm, S = 15 mm, Q = 50 kNUse Housel’s equation i.e. Q = Aq + PsA = contact areaq = bearing pressure beneath area A (constant)P = perimeter of footings = Perimeter shear (constant)Determine the load (in kN) on circular footing 1.2 m diameter that will cause a settlement of 15 mm.a)279.6b)402.18c)512.2d)558.8Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam.
Find important definitions, questions, meanings, examples, exercises and tests below for The results of two plate load tests performed on a given location with two circular plates are given below:1. Diameter = 750 mm, S = 15 mm, Q = 150 kN2. Diameter = 300 mm, S = 15 mm, Q = 50 kNUse Housel’s equation i.e. Q = Aq + PsA = contact areaq = bearing pressure beneath area A (constant)P = perimeter of footings = Perimeter shear (constant)Determine the load (in kN) on circular footing 1.2 m diameter that will cause a settlement of 15 mm.a)279.6b)402.18c)512.2d)558.8Correct answer is option 'A'. Can you explain this answer?.
Solutions for The results of two plate load tests performed on a given location with two circular plates are given below:1. Diameter = 750 mm, S = 15 mm, Q = 150 kN2. Diameter = 300 mm, S = 15 mm, Q = 50 kNUse Housel’s equation i.e. Q = Aq + PsA = contact areaq = bearing pressure beneath area A (constant)P = perimeter of footings = Perimeter shear (constant)Determine the load (in kN) on circular footing 1.2 m diameter that will cause a settlement of 15 mm.a)279.6b)402.18c)512.2d)558.8Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for GATE.
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Here you can find the meaning of The results of two plate load tests performed on a given location with two circular plates are given below:1. Diameter = 750 mm, S = 15 mm, Q = 150 kN2. Diameter = 300 mm, S = 15 mm, Q = 50 kNUse Housel’s equation i.e. Q = Aq + PsA = contact areaq = bearing pressure beneath area A (constant)P = perimeter of footings = Perimeter shear (constant)Determine the load (in kN) on circular footing 1.2 m diameter that will cause a settlement of 15 mm.a)279.6b)402.18c)512.2d)558.8Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
The results of two plate load tests performed on a given location with two circular plates are given below:1. Diameter = 750 mm, S = 15 mm, Q = 150 kN2. Diameter = 300 mm, S = 15 mm, Q = 50 kNUse Housel’s equation i.e. Q = Aq + PsA = contact areaq = bearing pressure beneath area A (constant)P = perimeter of footings = Perimeter shear (constant)Determine the load (in kN) on circular footing 1.2 m diameter that will cause a settlement of 15 mm.a)279.6b)402.18c)512.2d)558.8Correct answer is option 'A'. Can you explain this answer?, a detailed solution for The results of two plate load tests performed on a given location with two circular plates are given below:1. Diameter = 750 mm, S = 15 mm, Q = 150 kN2. Diameter = 300 mm, S = 15 mm, Q = 50 kNUse Housel’s equation i.e. Q = Aq + PsA = contact areaq = bearing pressure beneath area A (constant)P = perimeter of footings = Perimeter shear (constant)Determine the load (in kN) on circular footing 1.2 m diameter that will cause a settlement of 15 mm.a)279.6b)402.18c)512.2d)558.8Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of The results of two plate load tests performed on a given location with two circular plates are given below:1. Diameter = 750 mm, S = 15 mm, Q = 150 kN2. Diameter = 300 mm, S = 15 mm, Q = 50 kNUse Housel’s equation i.e. Q = Aq + PsA = contact areaq = bearing pressure beneath area A (constant)P = perimeter of footings = Perimeter shear (constant)Determine the load (in kN) on circular footing 1.2 m diameter that will cause a settlement of 15 mm.a)279.6b)402.18c)512.2d)558.8Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The results of two plate load tests performed on a given location with two circular plates are given below:1. Diameter = 750 mm, S = 15 mm, Q = 150 kN2. Diameter = 300 mm, S = 15 mm, Q = 50 kNUse Housel’s equation i.e. Q = Aq + PsA = contact areaq = bearing pressure beneath area A (constant)P = perimeter of footings = Perimeter shear (constant)Determine the load (in kN) on circular footing 1.2 m diameter that will cause a settlement of 15 mm.a)279.6b)402.18c)512.2d)558.8Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice GATE tests.