Consider the following pairs of complexes [CoF(NH3)5]2 and [Cr(OH2)6]...
Introduction:
In this question, we need to determine which pair of complexes will have the fastest electron transfer rate.
Explanation:
The electron transfer rate is determined by the ease with which an electron can be transferred from one complex to another. This is dependent on the relative oxidation states of the metals in the complexes.
Comparison of Complexes:
Let's compare the oxidation states of the metals in each pair of complexes:
- [CoF(NH3)5]2 and [Cr(OH2)6]2
- Co is in the +2 oxidation state and Cr is in the +2 oxidation state
- [Co(NH3)5(OH2)]3 and [Cr(OH2)6]2
- Co is in the +3 oxidation state and Cr is in the +2 oxidation state
- [Co(NH3)6]3 and [Cr(OH2)6]2
- Co is in the +3 oxidation state and Cr is in the +2 oxidation state
- [CoI(NH3)5]2 and [Cr(OH2)6]2
- Co is in the +2 oxidation state and Cr is in the +2 oxidation state
Explanation of Results:
From the above comparison, we can see that in all pairs of complexes, the oxidation state of Cr is the same. Therefore, the relative ease of electron transfer will depend on the oxidation state of Co.
- When Co is in the +2 oxidation state (pairs 1 and 4), the electron transfer rate will be slower as compared to when Co is in the +3 oxidation state (pairs 2 and 3).
- Therefore, the pair of complexes that will have the fastest electron transfer rate is [Co(NH3)5(OH2)]3 and [Cr(OH2)6]2.
Conclusion:
In conclusion, we can say that the electron transfer rate between two complexes depends on the relative oxidation states of the metals in the complexes. In this case, the pair of complexes [Co(NH3)5(OH2)]3 and [Cr(OH2)6]2 will have the fastest electron transfer rate.