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The first term and the last term of an arithmetic progression are 1 and 20 respectively find the number of term if the sum of all the terms is 420?
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The first term and the last term of an arithmetic progression are 1 an...
Problem Analysis:
We are given the first term (a) and last term (l) of an arithmetic progression, and we need to find the number of terms (n) if the sum of all the terms is 420.

Formula:
The formula to find the sum of an arithmetic progression is:
S = (n/2)(a + l)

Solution:
To solve this problem, we can use the formula for the sum of an arithmetic progression and substitute the given values.

Given:
First term (a) = 1
Last term (l) = 20
Sum of all terms (S) = 420

Substituting the given values into the formula:
420 = (n/2)(1 + 20)

Simplifying the equation:
420 = (n/2)(21)

Dividing both sides of the equation by 21:
20 = (n/2)

Multiplying both sides of the equation by 2:
40 = n

Therefore, the number of terms in the arithmetic progression is 40.

Final Answer:
The number of terms in the arithmetic progression is 40.
Community Answer
The first term and the last term of an arithmetic progression are 1 an...
40
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The first term and the last term of an arithmetic progression are 1 and 20 respectively find the number of term if the sum of all the terms is 420?
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