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A non concurrent forces acting on a wheel as shown in the Fig. find the resultant force. Also locate its position along the X-axis from centre. Radius of wheel = 20 cm. [Ans:R=95.23N, ά=72.570 , Mo=1158.50 N-cm, x = 12.75 cm, y = 40.62 cm]?
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A non concurrent forces acting on a wheel as shown in the Fig. find th...
Problem Statement:
A non-concurrent force system is acting on a wheel of radius 20 cm as shown in the figure. Find the magnitude and direction of the resultant force. Also, calculate the position of the resultant force along the X-axis from the centre of the wheel.
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Solution:
Given, radius of wheel (r) = 20 cm
The forces acting on the wheel are:
F1 = 80 N
F2 = 60 N
F3 = 100 N
F4 = 120 N
The angles made by the forces with the x-axis are:
θ1 = 60°
θ2 = 150°
θ3 = 240°
θ4 = 330°
Step 1: Finding the x and y components of each force
The x and y components of each force can be found using the following equations:
Fx = F cos(θ)
Fy = F sin(θ)
The x and y components of each force are:
F1x = 80 cos(60°) = 40 N
F1y = 80 sin(60°) = 69.28 N
F2x = 60 cos(150°) = -30 N
F2y = 60 sin(150°) = 51.96 N
F3x = 100 cos(240°) = -50 N
F3y = 100 sin(240°) = -86.6 N
F4x = 120 cos(330°) = 103.92 N
F4y = 120 sin(330°) = -60 N
Step 2: Finding the x and y components of the resultant force
The x and y components of the resultant force can be found by adding up the x and y components of each force.
Fx = ΣFx = F1x + F2x + F3x + F4x = 40 N - 30 N - 50 N + 103.92 N = 63.92 N
Fy = ΣF
A non-concurrent force system is acting on a wheel of radius 20 cm as shown in the figure. Find the magnitude and direction of the resultant force. Also, calculate the position of the resultant force along the X-axis from the centre of the wheel.
Solution:
Given, radius of wheel (r) = 20 cm
The forces acting on the wheel are:
F1 = 80 N
F2 = 60 N
F3 = 100 N
F4 = 120 N
The angles made by the forces with the x-axis are:
θ1 = 60°
θ2 = 150°
θ3 = 240°
θ4 = 330°
Step 1: Finding the x and y components of each force
The x and y components of each force can be found using the following equations:
Fx = F cos(θ)
Fy = F sin(θ)
The x and y components of each force are:
F1x = 80 cos(60°) = 40 N
F1y = 80 sin(60°) = 69.28 N
F2x = 60 cos(150°) = -30 N
F2y = 60 sin(150°) = 51.96 N
F3x = 100 cos(240°) = -50 N
F3y = 100 sin(240°) = -86.6 N
F4x = 120 cos(330°) = 103.92 N
F4y = 120 sin(330°) = -60 N
Step 2: Finding the x and y components of the resultant force
The x and y components of the resultant force can be found by adding up the x and y components of each force.
Fx = ΣFx = F1x + F2x + F3x + F4x = 40 N - 30 N - 50 N + 103.92 N = 63.92 N
Fy = ΣF
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A non concurrent forces acting on a wheel as shown in the Fig. find the resultant force. Also locate its position along the X-axis from centre. Radius of wheel = 20 cm. [Ans:R=95.23N, ά=72.570 , Mo=1158.50 N-cm, x = 12.75 cm, y = 40.62 cm]?
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A non concurrent forces acting on a wheel as shown in the Fig. find the resultant force. Also locate its position along the X-axis from centre. Radius of wheel = 20 cm. [Ans:R=95.23N, ά=72.570 , Mo=1158.50 N-cm, x = 12.75 cm, y = 40.62 cm]? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A non concurrent forces acting on a wheel as shown in the Fig. find the resultant force. Also locate its position along the X-axis from centre. Radius of wheel = 20 cm. [Ans:R=95.23N, ά=72.570 , Mo=1158.50 N-cm, x = 12.75 cm, y = 40.62 cm]? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A non concurrent forces acting on a wheel as shown in the Fig. find the resultant force. Also locate its position along the X-axis from centre. Radius of wheel = 20 cm. [Ans:R=95.23N, ά=72.570 , Mo=1158.50 N-cm, x = 12.75 cm, y = 40.62 cm]?.
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