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There are 500 children in a school. For a P.T. drill they have to stand in such a manner that number of rows is equal to number of columns. How many children would be left out in this arrangement?
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There are 500 children in a school. For a P.T. drill they have to stan...
Arranging Children in Rows and Columns


Given: 500 children

Objective: To arrange them in such a manner that the number of rows is equal to the number of columns.


Finding the square root of 500


To arrange the children in rows and columns, we need to find the square root of 500. The square root of 500 is approximately 22.36. However, we cannot have a decimal number of rows or columns, so we need to round down to the nearest whole number.


Therefore, the maximum number of rows and columns we can have is 22.


Finding the Number of Children Left Out


To find the number of children left out, we need to subtract the number of children in the arranged rows and columns from the total number of children.


The number of children in the arranged rows and columns is 22 x 22 = 484.


Therefore, the number of children left out is 500 - 484 = 16.


Conclusion


In conclusion, to arrange 500 children in rows and columns where the number of rows is equal to the number of columns, we can have a maximum of 22 rows and 22 columns. This would leave 16 children left out of the arrangement.
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There are 500 children in a school. For a P.T. drill they have to stand in such a manner that number of rows is equal to number of columns. How many children would be left out in this arrangement?
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