The transistor of a class A power amplifier is supplied from a 6V batt...
Analysis of Power Amplifier with Transistor
Given:
- Supply voltage (Vcc) = 6V
- Maximum collector current change (ΔIc) = 30 mA
- Loudspeaker impedance (RL) = 8 ohm
Calculations:
Direct Connection
When the loudspeaker is connected directly in the collector circuit, the power transferred to the loudspeaker can be calculated as follows:
Maximum collector current (Ic) = (Vcc / 2) / (RL / 2) = 6/16 = 0.375 A
Power transferred to loudspeaker = Ic² * RL = (0.375)² * 8 = 1.40625 W
Coupled through a Transformer
When the loudspeaker is coupled through a transformer for maximum power transfer, the power transferred to the loudspeaker can be calculated as follows:
Maximum power is transferred when the load impedance (RL) is equal to the reflected impedance of the transistor (Rc) as seen through the transformer.
Rc = Vcc / ΔIc = 6 / 0.03 = 200 ohm
The reflected impedance of Rc through the transformer can be calculated as follows:
R'c = Rc / (turns ratio)²
Taking turns ratio as n, R'c = 200 / n²
For maximum power transfer, RL = R'c
8 = 200 / n²
n² = 200 / 8 = 25
n = 5
Therefore, the turns ratio of the transformer should be 5.
Power transferred to loudspeaker = (Vcc / 2)² * RL / (RL + R'c)²
= (6 / 2)² * 8 / (8 + 200/5)²
= 1.875 mW
Conclusion:
The power transferred to the loudspeaker is higher when it is directly connected to the collector circuit than when it is coupled through a transformer for maximum power transfer. However, coupling through a transformer can provide impedance matching and isolation between the amplifier and the loudspeaker. The turns ratio of the transformer required for maximum power transfer is calculated to be 5.