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Which of the following reacts with benzene in presence of anhydrous aluminium chloride and forms acetophenone?
- a)CH3Cl
- b)CH3COOH
- c)CH3CHO
- d)CH3COCl
Correct answer is option 'D'. Can you explain this answer?
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Which of the following reacts with benzene in presence of anhydrous al...
Formation of Acetophenone from Benzene
In the presence of anhydrous aluminium chloride, benzene reacts with acetyl chloride (CH3COCl) to form acetophenone. The reaction is known as Friedel-Crafts acylation.
Mechanism of Friedel-Crafts Acylation
Step 1: Formation of acylium ion
Anhydrous aluminium chloride (AlCl3) acts as a Lewis acid and accepts a lone pair of electrons from the carbonyl oxygen of acetyl chloride. This leads to the formation of an acylium ion (CH3CO+).
CH3COCl + AlCl3 → CH3CO+ + AlCl4-
Step 2: Attack of benzene on acylium ion
The aromatic ring of benzene acts as a nucleophile and attacks the positively charged acylium ion. This leads to the formation of an intermediate compound (an arenium ion).
CH3CO+ + C6H6 → C6H5COCH3+
Step 3: Removal of proton
The intermediate compound (arenium ion) loses a proton to form the final product, acetophenone.
C6H5COCH3+ → C6H5COCH3 + H+
Thus, the overall reaction can be represented as:
C6H6 + CH3COCl → C6H5COCH3 + HCl
Conclusion
In the presence of anhydrous aluminium chloride, benzene reacts with acetyl chloride to form acetophenone via Friedel-Crafts acylation. The reaction involves the formation of an acylium ion, attack of benzene on the acylium ion, and removal of a proton to form the final product.
In the presence of anhydrous aluminium chloride, benzene reacts with acetyl chloride (CH3COCl) to form acetophenone. The reaction is known as Friedel-Crafts acylation.
Mechanism of Friedel-Crafts Acylation
Step 1: Formation of acylium ion
Anhydrous aluminium chloride (AlCl3) acts as a Lewis acid and accepts a lone pair of electrons from the carbonyl oxygen of acetyl chloride. This leads to the formation of an acylium ion (CH3CO+).
CH3COCl + AlCl3 → CH3CO+ + AlCl4-
Step 2: Attack of benzene on acylium ion
The aromatic ring of benzene acts as a nucleophile and attacks the positively charged acylium ion. This leads to the formation of an intermediate compound (an arenium ion).
CH3CO+ + C6H6 → C6H5COCH3+
Step 3: Removal of proton
The intermediate compound (arenium ion) loses a proton to form the final product, acetophenone.
C6H5COCH3+ → C6H5COCH3 + H+
Thus, the overall reaction can be represented as:
C6H6 + CH3COCl → C6H5COCH3 + HCl
Conclusion
In the presence of anhydrous aluminium chloride, benzene reacts with acetyl chloride to form acetophenone via Friedel-Crafts acylation. The reaction involves the formation of an acylium ion, attack of benzene on the acylium ion, and removal of a proton to form the final product.
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Which of the following reacts with benzene in presence of anhydrous aluminium chloride and forms acetophenone?a)CH3Clb)CH3COOHc)CH3CHOd)CH3COClCorrect answer is option 'D'. Can you explain this answer?
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Which of the following reacts with benzene in presence of anhydrous aluminium chloride and forms acetophenone?a)CH3Clb)CH3COOHc)CH3CHOd)CH3COClCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Which of the following reacts with benzene in presence of anhydrous aluminium chloride and forms acetophenone?a)CH3Clb)CH3COOHc)CH3CHOd)CH3COClCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Which of the following reacts with benzene in presence of anhydrous aluminium chloride and forms acetophenone?a)CH3Clb)CH3COOHc)CH3CHOd)CH3COClCorrect answer is option 'D'. Can you explain this answer?.
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