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Cyclic heat engine operating between Source temperature 600 degree nd sink temperature 20 degree Celsius at least rate of heating rejection work output of engine will be?
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Cyclic heat engine operating between Source temperature 600 degree nd ...
- Source temperature: 600°C
- Sink temperature: 20°C

Calculation of maximum efficiency:
- The maximum efficiency of a Carnot cycle is given by:
\[ \eta = 1 - \frac{T_{sink}}{T_{source}} \]
\[ \eta = 1 - \frac{20+273}{600+273} = 1 - \frac{293}{873} \approx 0.66 \]

Calculation of work output:
- The work output of the engine is given by:
\[ W = Q_{source} - Q_{sink} \]
where,
\[ Q_{source} = Q_{sink} + W \]
\[ Q_{source} = \frac{T_{source}}{T_{source} - T_{sink}} \times Q_{sink} \]
\[ Q_{source} = \frac{600+273}{600+273-20-273} \times Q_{sink} \]
\[ Q_{source} = \frac{873}{300} \times Q_{sink} \]
\[ Q_{source} = 2.91 \times Q_{sink} \]
- Therefore, the work output of the engine will be 1.91 times the rate of heating rejection.
In conclusion, the work output of the cyclic heat engine operating between a source temperature of 600°C and a sink temperature of 20°C will be 1.91 times the rate of heating rejection. The maximum efficiency of the engine is approximately 66%.
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Cyclic heat engine operating between Source temperature 600 degree nd sink temperature 20 degree Celsius at least rate of heating rejection work output of engine will be?
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