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Determine the molecular formula of an oxide of nitrogen containing the same of its own volume of nitrogen if its vapour density is 54. [3 2]?
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Determine the molecular formula of an oxide of nitrogen containing the...
Introduction:
The molecular formula of an oxide of nitrogen is to be determined based on given information.

Given:
- Vapour density = 54
- Contains the same volume of nitrogen

Solution:
To determine the molecular formula of the oxide of nitrogen, we need to follow the steps given below:

1. Calculate the molecular weight of the oxide of nitrogen by using the formula:

Molecular weight = 2 × Vapour density

Here, vapour density is given as 54. Therefore,

Molecular weight = 2 × 54 = 108

2. Determine the atomic weight of nitrogen. Nitrogen has an atomic weight of 14.

3. Calculate the number of nitrogen atoms present in the oxide of nitrogen.

Let the number of nitrogen atoms be x.

Then, x × 14 = molecular weight - atomic weight of oxygen

= 108 - 16 = 92

Therefore, x = 6.57 ≈ 7 (rounded off to the nearest whole number)

4. Determine the molecular formula of the oxide of nitrogen.

The molecular formula of the oxide of nitrogen can be represented as N2Ox.

Since the oxide of nitrogen contains seven nitrogen atoms, x = 7.

Therefore, the molecular formula of the oxide of nitrogen is N2O7.

Conclusion:
Hence, the molecular formula of the oxide of nitrogen is N2O7.
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Determine the molecular formula of an oxide of nitrogen containing the same of its own volume of nitrogen if its vapour density is 54. [3 2]?
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