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Rajesh got twice as many sums wrong as he got right. If he attempted 84 sums in all. How many sums did he solve correctly?
- a)24
- b)28
- c)26
- d)32
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
Rajesh got twice as many sums wrong as he got right. If he attempted 8...
Problem:
Rajesh got twice as many sums wrong as he got right. If he attempted 84 sums in total, how many sums did he solve correctly?
Solution:
Let's assume that Rajesh got x sums right.
According to the problem, he got twice as many sums wrong as he got right. Therefore, the number of sums he got wrong is 2x.
The total number of sums Rajesh attempted is given as 84.
So, we can write the equation:
x + 2x = 84
Solving the Equation:
Combining like terms on the left side of the equation:
3x = 84
Dividing both sides of the equation by 3 to isolate x:
x = 84/3
x = 28
Therefore, Rajesh solved 28 sums correctly.
Explanation:
To solve this problem, we assume that Rajesh solved x sums correctly. As the problem states that he got twice as many sums wrong as he got right, the number of sums he got wrong is 2x.
We know that the total number of sums Rajesh attempted is 84. So, we can write the equation x + 2x = 84 to represent the total number of sums attempted.
By combining like terms on the left side of the equation, we get 3x = 84. Dividing both sides of the equation by 3 isolates x, giving us x = 28.
Hence, Rajesh solved 28 sums correctly.
Rajesh got twice as many sums wrong as he got right. If he attempted 84 sums in total, how many sums did he solve correctly?
Solution:
Let's assume that Rajesh got x sums right.
According to the problem, he got twice as many sums wrong as he got right. Therefore, the number of sums he got wrong is 2x.
The total number of sums Rajesh attempted is given as 84.
So, we can write the equation:
x + 2x = 84
Solving the Equation:
Combining like terms on the left side of the equation:
3x = 84
Dividing both sides of the equation by 3 to isolate x:
x = 84/3
x = 28
Therefore, Rajesh solved 28 sums correctly.
Explanation:
To solve this problem, we assume that Rajesh solved x sums correctly. As the problem states that he got twice as many sums wrong as he got right, the number of sums he got wrong is 2x.
We know that the total number of sums Rajesh attempted is 84. So, we can write the equation x + 2x = 84 to represent the total number of sums attempted.
By combining like terms on the left side of the equation, we get 3x = 84. Dividing both sides of the equation by 3 isolates x, giving us x = 28.
Hence, Rajesh solved 28 sums correctly.
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Community Answer
Rajesh got twice as many sums wrong as he got right. If he attempted 8...
Let Rajesh solves x sums correctly. Right sums = x, wrong sums = 2x
∴ x + 2x = 84
⇒ 3x = 84
⇒ x = 28
∴ x + 2x = 84
⇒ 3x = 84
⇒ x = 28
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Rajesh got twice as many sums wrong as he got right. If he attempted 84 sums in all. Howmany sums did he solve correctly?a)24b)28c)26d)32Correct answer is option 'B'. Can you explain this answer?
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