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A constant force acts on an object of mass 5 kg for a duration of 2 seconds. It increases the object’s velocity from 3 m/s to 7m/s, find the magnitude of the force applied on the object.
- a)10 N
- b)20 N
- c)25 N
- d)30 N
Correct answer is option 'A'. Can you explain this answer?
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A constant force acts on an object of mass 5 kg for a duration of 2 s...
Given data:
- Mass of the object (m) = 5 kg
- Initial velocity (u) = 3 m/s
- Final velocity (v) = 7 m/s
- Time duration (t) = 2 seconds
Calculation:
- Using the formula:
\[ F = \frac{m(v-u)}{t} \]
- Substituting the given values:
\[ F = \frac{5(7-3)}{2} = \frac{5 \times 4}{2} = \frac{20}{2} = 10 \, N \]
Therefore, the magnitude of the force applied on the object is 10 N. Hence, option 'A' is the correct answer.
- Mass of the object (m) = 5 kg
- Initial velocity (u) = 3 m/s
- Final velocity (v) = 7 m/s
- Time duration (t) = 2 seconds
Calculation:
- Using the formula:
\[ F = \frac{m(v-u)}{t} \]
- Substituting the given values:
\[ F = \frac{5(7-3)}{2} = \frac{5 \times 4}{2} = \frac{20}{2} = 10 \, N \]
Therefore, the magnitude of the force applied on the object is 10 N. Hence, option 'A' is the correct answer.
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Community Answer
A constant force acts on an object of mass 5 kg for a duration of 2 s...
F = m(v-u)/t = 5(7-3)/2 = 10N
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A constant force acts on an object of mass 5 kg for a duration of 2 seconds. It increases the object’s velocity from 3 m/s to 7m/s, find the magnitude of the force applied on the object.a)10 Nb)20 Nc)25 Nd)30 NCorrect answer is option 'A'. Can you explain this answer?
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