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A constant force acts on an object of mass 4kg for a duration of 2s. It increases the object's velocity from 4m/s to 8m/s. Find the magnitude of the applied force. Now if the force was applied for a duration of 5s, what would be the final velocity of the object?
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A constant force acts on an object of mass 4kg for a duration of 2s. I...
Calculating the magnitude of the applied force:
- Initial velocity, u = 4 m/s
- Final velocity, v = 8 m/s
- Mass, m = 4 kg
- Duration, t = 2 s
Using the equation of motion:
v = u + at
8 = 4 + a * 2
a = 2 m/s²
Now, using Newton's second law of motion:
F = ma
F = 4 * 2

Therefore, the magnitude of the applied force is 8 N.

Finding the final velocity for a duration of 5 seconds:
- Initial velocity, u = 4 m/s
- Duration, t = 5 s
Using the equation of motion:
v = u + at
v = 4 + 2 * 5
v = 14 m/s

Therefore, the final velocity of the object when the force is applied for 5 seconds would be 14 m/s.
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A constant force acts on an object of mass 4kg for a duration of 2s. It increases the object's velocity from 4m/s to 8m/s. Find the magnitude of the applied force. Now if the force was applied for a duration of 5s, what would be the final velocity of the object?
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A constant force acts on an object of mass 4kg for a duration of 2s. It increases the object's velocity from 4m/s to 8m/s. Find the magnitude of the applied force. Now if the force was applied for a duration of 5s, what would be the final velocity of the object? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A constant force acts on an object of mass 4kg for a duration of 2s. It increases the object's velocity from 4m/s to 8m/s. Find the magnitude of the applied force. Now if the force was applied for a duration of 5s, what would be the final velocity of the object? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A constant force acts on an object of mass 4kg for a duration of 2s. It increases the object's velocity from 4m/s to 8m/s. Find the magnitude of the applied force. Now if the force was applied for a duration of 5s, what would be the final velocity of the object?.
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