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Which of the following is correct arrangement of decreasing order of force of attraction between
particles?
  • a)
    Water, air, chalk
  • b)
    Sugar, alcohol, nitrogen
  • c)
    Sulphur dioxide, carbon disulphide, sulphur
  • d)
    Oxygen, water sugar.
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
Which of the following is correct arrangement of decreasing order of ...
Decreasing Order of Force of Attraction Between Particles

Sugar, alcohol, and nitrogen have intermolecular forces of attraction that are stronger than those between water, air, and chalk. Sulphur dioxide, carbon disulphide, and sulphur have even stronger forces of attraction than the former three, while oxygen, water, and sugar have the weakest forces of attraction.

Explanation:

Intermolecular forces of attraction refer to the forces that hold the particles of a substance together. These forces include Van der Waals forces, dipole-dipole interactions, and hydrogen bonding. The strength of these forces varies depending on the type of particles involved and their arrangement.

The correct arrangement of decreasing order of force of attraction between particles is option B (sugar, alcohol, nitrogen). Sugar and alcohol have strong intermolecular forces of attraction due to the presence of hydrogen bonding between their molecules. Nitrogen also has strong intermolecular forces of attraction due to the presence of Van der Waals forces between its molecules.

Option A (water, air, chalk) has weaker intermolecular forces of attraction than option B. Water has hydrogen bonding between its molecules, but air and chalk have weaker Van der Waals forces between their particles.

Option C (sulphur dioxide, carbon disulphide, sulphur) has even stronger intermolecular forces of attraction than option B. Sulphur dioxide and carbon disulphide have dipole-dipole interactions and Van der Waals forces between their molecules, while sulphur has strong Van der Waals forces between its particles.

Option D (oxygen, water, sugar) has the weakest intermolecular forces of attraction among the given options. Oxygen has weak Van der Waals forces between its molecules, while water and sugar have weaker hydrogen bonding than sugar and alcohol.

In summary, the correct arrangement of decreasing order of force of attraction between particles is:

1. Sulphur dioxide, carbon disulphide, sulphur
2. Sugar, alcohol, nitrogen
3. Water, air, chalk
4. Oxygen, water, sugar.
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Community Answer
Which of the following is correct arrangement of decreasing order of ...
The substances in decreasing order of force of attraction between the particles are-
  1. Sugar (being a solid, has the highest force of attraction between the particles)
  2. Alcohol (being a liquid, has comparatively lesser force of attraction between the particles than sugar)
  3. Nitrogen (being a gas, has the lowest force of attraction between the particles)
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Which of the following is correct arrangement of decreasing order of force of attraction betweenparticles?a)Water, air, chalkb)Sugar, alcohol, nitrogenc)Sulphur dioxide, carbon disulphide, sulphurd)Oxygen, water sugar.Correct answer is option 'B'. Can you explain this answer?
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