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The mean and SD for a, b and 2 are 3 and 2/√3 respectively, the value of ab would be?
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The mean and SD for a, b and 2 are 3 and 2/√3 respectively, the value ...
Calculation of ab given mean and SD of a, b and 2


To calculate the value of ab, we need to use the formula:


SDab = √[(SDa)2(b)2 + (SDb)2(a)2 + 2(a)(b)(Covab)]


where SDa, SDb, Covab are the standard deviations and covariance of a and b respectively.


Finding the covariance of a and b


Since we do not have the covariance of a and b, we need to estimate it using the formula:


Covab = [E(ab) - E(a)E(b)]


where E(ab), E(a), and E(b) are the expected values of ab, a, and b respectively.


Finding the expected values of a, b, and ab


Since we have the mean of a, b, and 2, we can find the expected values of a and b as follows:


E(a) = 3

E(b) = 3

E(2) = 2


Now, we need to find the expected value of ab:


E(ab) = E(a)E(b) + Covab


Finding the standard deviations of a, b, and ab


Now that we have the expected values of a, b, and ab, we can find the standard deviations of a, b, and ab as follows:


SDa = 2/√3

SDb = 2/√3

SDab = √[(SDa)2(b)2 + (SDb)2(a)2 + 2(a)(b)(Covab)]


Calculating the value of ab


Now that we have all the necessary values, we can calculate the value of ab as follows:


ab = (E(ab) - E(a)E(b))/Covab


Substituting the values we get:


ab = (9 - 9)/Covab

ab = 0/Covab

ab = 0


Conclusion


Therefore, the value of ab is 0 given the mean and SD of a, b, and 2 are 3 and 2/√3 respectively.
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The mean and SD for a, b and 2 are 3 and 2/√3 respectively, the value of ab would be?
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