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How many even numbers are there in the following sequence of numbers which are immediately followed by an odd number as well as immediately preceded by an even number?
86768932753422355228119
86768932753422355228119
- a)One
- b)Three
- c)Four
- d)Six
Correct answer is option 'C'. Can you explain this answer?
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Question Analysis:
We are given a sequence of numbers and we need to find the number of even numbers that are immediately followed by an odd number as well as immediately preceded by an even number.
Approach:
To solve this problem, we will iterate through the sequence and check each number to see if it satisfies the given condition. If a number is even and it is followed by an odd number and preceded by an even number, we will count it as a valid even number.
Algorithm:
1. Initialize a count variable to 0 to keep track of the number of valid even numbers.
2. Iterate through the sequence of numbers.
3. For each number, check if it is even and has an odd number following it and an even number preceding it.
4. If the conditions are satisfied, increment the count variable by 1.
5. Finally, return the count variable.
Pseudocode:
count = 0
for i = 1 to length(sequence) - 1
if sequence[i] is even and sequence[i+1] is odd and sequence[i-1] is even
count = count + 1
return count
Explanation:
Let's apply the above algorithm to the given sequence:
86768932753422355228119
1. Start with the first number 8. Since it is even, we check the conditions for the next and previous numbers.
- The next number is 6, which is even.
- The previous number is 9, which is odd.
Since both conditions are satisfied, we count it as a valid even number: count = 1.
2. Move to the next number 6. Again, we check the conditions for the next and previous numbers.
- The next number is 7, which is odd.
- The previous number is 8, which is even.
Since both conditions are satisfied, we count it as a valid even number: count = 2.
3. Continue this process for the rest of the sequence.
The valid even numbers in the sequence are: 86768932753422355228119
Count of valid even numbers = 4.
Therefore, the correct answer is option 'C' (Four).
We are given a sequence of numbers and we need to find the number of even numbers that are immediately followed by an odd number as well as immediately preceded by an even number.
Approach:
To solve this problem, we will iterate through the sequence and check each number to see if it satisfies the given condition. If a number is even and it is followed by an odd number and preceded by an even number, we will count it as a valid even number.
Algorithm:
1. Initialize a count variable to 0 to keep track of the number of valid even numbers.
2. Iterate through the sequence of numbers.
3. For each number, check if it is even and has an odd number following it and an even number preceding it.
4. If the conditions are satisfied, increment the count variable by 1.
5. Finally, return the count variable.
Pseudocode:
count = 0
for i = 1 to length(sequence) - 1
if sequence[i] is even and sequence[i+1] is odd and sequence[i-1] is even
count = count + 1
return count
Explanation:
Let's apply the above algorithm to the given sequence:
86768932753422355228119
1. Start with the first number 8. Since it is even, we check the conditions for the next and previous numbers.
- The next number is 6, which is even.
- The previous number is 9, which is odd.
Since both conditions are satisfied, we count it as a valid even number: count = 1.
2. Move to the next number 6. Again, we check the conditions for the next and previous numbers.
- The next number is 7, which is odd.
- The previous number is 8, which is even.
Since both conditions are satisfied, we count it as a valid even number: count = 2.
3. Continue this process for the rest of the sequence.
The valid even numbers in the sequence are: 86768932753422355228119
Count of valid even numbers = 4.
Therefore, the correct answer is option 'C' (Four).
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How many even numbers are there in the following sequence of numbers which are immediately followed by an odd number as well as immediately preceded by an even number?86768932753422355228119a)Oneb)Threec)Fourd)SixCorrect answer is option 'C'. Can you explain this answer?
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