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Between a shaft and sleeve is 6 poise. The shaft is of diameter 0.4 m and roates at 190 r.p.m. Calculate the power lost in the bearing for a sleeve length of 90 mm. The thickness of the oil film is 1.5mm.?
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Between a shaft and sleeve is 6 poise. The shaft is of diameter 0.4 m ...
Calculation of Power Lost in the Bearing

Given data:
- Viscosity of the oil film (μ) = 6 poise
- Diameter of the shaft (D) = 0.4 m
- Rotational speed of the shaft (N) = 190 r.p.m
- Length of the sleeve (L) = 90 mm
- Thickness of the oil film (h) = 1.5 mm

Conversion of Units:
To perform the calculations, it is necessary to convert the given units to a consistent system. Since the viscosity is given in poise, it needs to be converted to Pascal-seconds (Pa.s) using the conversion factor 1 poise = 0.1 Pa.s. Similarly, the length of the sleeve and the thickness of the oil film need to be converted to meters.

1 poise = 0.1 Pa.s
90 mm = 0.09 m
1.5 mm = 0.0015 m

Calculation of Oil Film Velocity:
The oil film velocity (V) can be calculated using the formula:

V = π * D * N / 60

Where:
π = 3.14 (approximation of the mathematical constant π)
D = Diameter of the shaft
N = Rotational speed of the shaft in revolutions per minute (r.p.m)

Substituting the given values:
V = 3.14 * 0.4 * 190 / 60

Calculation of Shear Stress:
The shear stress (τ) in the oil film can be calculated using the formula:

τ = μ * V / h

Where:
μ = Viscosity of the oil film
V = Oil film velocity
h = Thickness of the oil film

Substituting the given values:
τ = 6 * (3.14 * 0.4 * 190 / 60) / 0.0015

Calculation of Power Lost:
The power lost in the bearing (P) can be calculated using the formula:

P = τ * A * L

Where:
P = Power lost in the bearing
τ = Shear stress in the oil film
A = Cross-sectional area of the oil film
L = Length of the sleeve

The cross-sectional area of the oil film (A) can be calculated using the formula:

A = π * D * h

Substituting the given values:
A = 3.14 * 0.4 * 0.0015

Finally, substituting the values of τ, A, and L into the power lost formula, we can calculate the power lost in the bearing (P).
Community Answer
Between a shaft and sleeve is 6 poise. The shaft is of diameter 0.4 m ...
P=716w
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Between a shaft and sleeve is 6 poise. The shaft is of diameter 0.4 m and roates at 190 r.p.m. Calculate the power lost in the bearing for a sleeve length of 90 mm. The thickness of the oil film is 1.5mm.?
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Between a shaft and sleeve is 6 poise. The shaft is of diameter 0.4 m and roates at 190 r.p.m. Calculate the power lost in the bearing for a sleeve length of 90 mm. The thickness of the oil film is 1.5mm.? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about Between a shaft and sleeve is 6 poise. The shaft is of diameter 0.4 m and roates at 190 r.p.m. Calculate the power lost in the bearing for a sleeve length of 90 mm. The thickness of the oil film is 1.5mm.? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Between a shaft and sleeve is 6 poise. The shaft is of diameter 0.4 m and roates at 190 r.p.m. Calculate the power lost in the bearing for a sleeve length of 90 mm. The thickness of the oil film is 1.5mm.?.
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