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An oil of vicosity 7 poise is used for lubrication between s
haft and sleeve. The diameter of shaft is 0.6 m and it rota
tes is 360 rpm. Calculate the power lost in oil for a sleeve
length of 160mm. The thickness of oil film is 1.0mm
Ans 25.31 kW?
haft and sleeve. The diameter of shaft is 0.6 m and it rota
tes is 360 rpm. Calculate the power lost in oil for a sleeve
length of 160mm. The thickness of oil film is 1.0mm
Ans 25.31 kW?
Most Upvoted Answer
An oil of vicosity 7 poise is used for lubrication between shaft and s...
Calculation of Power Lost in Oil for Lubrication
Power lost in oil (P) = (2πd3μNL)/(3Lh2)
Substituting the values in the above formula, we get
P = (2π x 0.63 x 7 x 360)/(3 x 0.16 x 10-3)
P = 25308.75 W or 25.31 kW (approx.)
Therefore, the power lost in oil for lubrication is 25.31 kW.
The given problem can be solved using the formula for power lost in oil for lubrication. This formula is derived based on the assumption that the oil film is maintained under laminar flow conditions. The power lost in oil is the power required to overcome the viscous resistance of the oil film. This power is proportional to the viscosity of oil, the diameter of the shaft, the rotational speed, and the length of the sleeve. It is inversely proportional to the thickness of the oil film. Substituting the given values in this formula, we get the power lost in oil as 25.31 kW.
Given Parameters:
- Viscosity of oil (μ) = 7 poise
- Diameter of shaft (d) = 0.6 m
- Rotational speed (N) = 360 rpm
- Sleeve length (L) = 160 mm
- Thickness of oil film (h) = 1.0 mm
Formula Used:
Power lost in oil (P) = (2πd3μNL)/(3Lh2)
Calculation:
Substituting the values in the above formula, we get
P = (2π x 0.63 x 7 x 360)/(3 x 0.16 x 10-3)
P = 25308.75 W or 25.31 kW (approx.)
Therefore, the power lost in oil for lubrication is 25.31 kW.
Explanation:
The given problem can be solved using the formula for power lost in oil for lubrication. This formula is derived based on the assumption that the oil film is maintained under laminar flow conditions. The power lost in oil is the power required to overcome the viscous resistance of the oil film. This power is proportional to the viscosity of oil, the diameter of the shaft, the rotational speed, and the length of the sleeve. It is inversely proportional to the thickness of the oil film. Substituting the given values in this formula, we get the power lost in oil as 25.31 kW.
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An oil of vicosity 7 poise is used for lubrication between shaft and sleeve. The diameter of shaft is 0.6 m and it rotates is 360 rpm. Calculate the power lost in oil for a sleevelength of 160mm. The thickness of oil film is 1.0mmAns 25.31 kW?
Question Description
An oil of vicosity 7 poise is used for lubrication between shaft and sleeve. The diameter of shaft is 0.6 m and it rotates is 360 rpm. Calculate the power lost in oil for a sleevelength of 160mm. The thickness of oil film is 1.0mmAns 25.31 kW? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about An oil of vicosity 7 poise is used for lubrication between shaft and sleeve. The diameter of shaft is 0.6 m and it rotates is 360 rpm. Calculate the power lost in oil for a sleevelength of 160mm. The thickness of oil film is 1.0mmAns 25.31 kW? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An oil of vicosity 7 poise is used for lubrication between shaft and sleeve. The diameter of shaft is 0.6 m and it rotates is 360 rpm. Calculate the power lost in oil for a sleevelength of 160mm. The thickness of oil film is 1.0mmAns 25.31 kW?.
An oil of vicosity 7 poise is used for lubrication between shaft and sleeve. The diameter of shaft is 0.6 m and it rotates is 360 rpm. Calculate the power lost in oil for a sleevelength of 160mm. The thickness of oil film is 1.0mmAns 25.31 kW? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about An oil of vicosity 7 poise is used for lubrication between shaft and sleeve. The diameter of shaft is 0.6 m and it rotates is 360 rpm. Calculate the power lost in oil for a sleevelength of 160mm. The thickness of oil film is 1.0mmAns 25.31 kW? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An oil of vicosity 7 poise is used for lubrication between shaft and sleeve. The diameter of shaft is 0.6 m and it rotates is 360 rpm. Calculate the power lost in oil for a sleevelength of 160mm. The thickness of oil film is 1.0mmAns 25.31 kW?.
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An oil of vicosity 7 poise is used for lubrication between shaft and sleeve. The diameter of shaft is 0.6 m and it rotates is 360 rpm. Calculate the power lost in oil for a sleevelength of 160mm. The thickness of oil film is 1.0mmAns 25.31 kW?, a detailed solution for An oil of vicosity 7 poise is used for lubrication between shaft and sleeve. The diameter of shaft is 0.6 m and it rotates is 360 rpm. Calculate the power lost in oil for a sleevelength of 160mm. The thickness of oil film is 1.0mmAns 25.31 kW? has been provided alongside types of An oil of vicosity 7 poise is used for lubrication between shaft and sleeve. The diameter of shaft is 0.6 m and it rotates is 360 rpm. Calculate the power lost in oil for a sleevelength of 160mm. The thickness of oil film is 1.0mmAns 25.31 kW? theory, EduRev gives you an
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