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Bisector AD of ∠BAC of ∆ABC passes through the center of the circumcircle of ∆ABC, then,
  • a)
    AB ≠ AC
  • b)
    AB = AC
  • c)
    BC = AC
  • d)
    BC = AB
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
Bisector AD of ∠BAC of ABC passes through the center of the circum...
∵ AD is the bisector of ∠BAC

∴ AD is the ⊥ bisector of BC. 
∵ O is the circumcentre of ∆ABC.
∴ AB = AC [∵ ∠ABD = ∠ACB]
(By using ∆ABD ≅ ∆ACD)
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Community Answer
Bisector AD of ∠BAC of ABC passes through the center of the circum...
Triangle ABC is a line segment that divides the angle BAC into two equal angles. In other words, angle BAD is equal to angle CAD. This line segment is called the angle bisector because it bisects the angle.

The bisector AD can be constructed by using a compass and a straightedge. Here is one way to construct the bisector:

1. Draw triangle ABC with points A, B, and C.
2. Take your compass and open it to any convenient radius. With the compass centered at point A, draw an arc that intersects both sides of angle BAC. Label the points of intersection as D and E.
3. With the compass still set at the same radius, place the compass point at point D and draw an arc that intersects the previously drawn arc. Label this point of intersection as F.
4. Use a straightedge to draw a line segment from point A to point F. This line segment is the bisector AD of angle BAC.

Note that the resulting line segment AD divides angle BAC into two equal angles, angle BAD and angle CAD.
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