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The area of an isosceles triangles whose equal sides are 12cm and the other side is 6cm long, will be :
  • a)
    3 √15 cm2
  • b)
    6 √15 cm2
  • c)
    9 √15 cm2
  • d)
    12√15 cm2
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
The area of an isosceles triangles whose equal sides are 12cm and the ...
The area of an isosceles triangle can be found using the formula:

Area = (base * height) / 2

In this case, the base is the side that is 6cm long, and the height is the perpendicular distance from the base to the vertex of the triangle.

Since the triangle is isosceles, the height bisects the base and divides it into two equal parts.

Therefore, each part of the base is 6cm / 2 = 3cm.

Using the Pythagorean theorem, we can find the height:

(12cm)^2 = (3cm)^2 + height^2

144cm^2 = 9cm^2 + height^2

height^2 = 144cm^2 - 9cm^2

height^2 = 135cm^2

height = sqrt(135cm^2)

height = 11.61cm

Substituting the values into the formula:

Area = (6cm * 11.61cm) / 2 = 69.66cm^2

Therefore, the area of the isosceles triangle is approximately 69.66cm^2.

So the correct answer would be:

b) 69.66cm^2
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Community Answer
The area of an isosceles triangles whose equal sides are 12cm and the ...
In ∆ABD,

AB2 + BD2 = AD2
⇒ AD2 = AB2 – BD2

⇒ AD = √135 = 3√15 cm.
∴ area (∆ABC) = 
= 9√15 cm2
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