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If a square and rhombus have same perimeter, and area of square is S and area of rhombus is R, then
  • a)
    S > R
  • b)
    R > S
  • c)
    R = S
  • d)
    data insufficient 
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
If a square and rhombus have same perimeter, and area of square is S a...

Area of square = a2
Area of rhombus = a2 sin θ
∵ sin θ < 1
∴ a2 > a2 sin θ
 ar (square) > ar (rhombus)
⇒ S > R
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Community Answer
If a square and rhombus have same perimeter, and area of square is S a...
Explanation:

Perimeter of Square and Rhombus:
- Let the side length of the square be 'a' and the side length of the rhombus be 'b'.
- Since the perimeter of a square is 4a and the perimeter of a rhombus is 4b, given that they have the same perimeter, we have 4a = 4b.

Area of Square and Rhombus:
- The area of a square is given by S = a^2.
- The area of a rhombus is given by R = (1/2) x (diagonal 1) x (diagonal 2).

Comparing Areas:
- For the square, S = a^2.
- For the rhombus, R = (1/2) x (diagonal 1) x (diagonal 2) < (1/2)="" x="" (2a)="" x="" (2a)="" />

Conclusion:
- Since 2a^2 > a^2, we can conclude that the area of the rhombus (R) is greater than the area of the square (S) when they have the same perimeter.
- Therefore, the correct answer is option 'A' - S > R.
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