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A positive number is 5 times another number. If 21 is added to both the numbers , then one of new numbers becomes twice the other new number. What are the numbers ?
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A positive number is 5 times another number. If 21 is added to both th...
**Problem Analysis:**

Let's assume that the first number is x and the second number is y.

According to the problem, we have the following information:

- The first number is 5 times the second number: x = 5y
- If 21 is added to both numbers, one of the new numbers becomes twice the other new number: (x + 21) = 2(y + 21)

**Solution:**

To find the values of x and y, we need to solve the above two equations simultaneously.

**Step 1: Substitute the value of x from the first equation into the second equation.**

(5y + 21) = 2(y + 21)

**Step 2: Expand the equation by removing the brackets.**

5y + 21 = 2y + 42

**Step 3: Simplify the equation by combining like terms.**

5y - 2y = 42 - 21

3y = 21

**Step 4: Divide both sides of the equation by 3 to solve for y.**

y = 7

**Step 5: Substitute the value of y into the first equation to find the value of x.**

x = 5(7)

x = 35

**Step 6: Check the solution by substituting the values of x and y into the second equation.**

(35 + 21) = 2(7 + 21)

56 = 2(28)

56 = 56

**Step 7: Conclusion**

The numbers are x = 35 and y = 7.
Community Answer
A positive number is 5 times another number. If 21 is added to both th...
Let the 1st number be x
The 2nd be 5x
Adding 21 to both the numbers
X+21. 5x+21

A/Q

5x+21=2(x+21)
5x +21=2x+42
5x-2x=42-21
3x=21
X=21/3
X=7
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A positive number is 5 times another number. If 21 is added to both the numbers , then one of new numbers becomes twice the other new number. What are the numbers ?
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