Three consecutive natural numbers are such that three times the middle...
Problem Statement:
We are given three consecutive natural numbers. Let's assume the middle number as 'x'. According to the question, three times the middle number should be greater than the sum of the other two numbers by 11.
Let's solve the problem step by step:
Step 1: Define the numbers:
Let's assume the three consecutive natural numbers as 'x-1', 'x', and 'x+1'. Here, 'x' is the middle number.
Step 2: Formulate the equation:
According to the given condition, three times the middle number should be greater than the sum of the other two numbers by 11. Mathematically, we can represent this as:
3x = (x-1) + (x+1) + 11
Step 3: Simplify the equation:
3x = 2x + 11
3x - 2x = 11
x = 11
Step 4: Find the numbers:
Now that we have found the value of 'x' as 11, we can substitute it back into our assumed numbers.
The three consecutive natural numbers are 10, 11, and 12.
Conclusion:
The three consecutive natural numbers are 10, 11, and 12.
Three consecutive natural numbers are such that three times the middle...
GIVEN:
Let the middle no. be = x
Then smaller no. is = x-1
And greater no. is = x+2
So,
3x = x-1 + x + 1 + 11
3x - 2x = 11
x =11
FIRST NO. IS x-1
11-1
10
SECOND NO. IS X
11
THIRD NO. IS x+1
11+1
12