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The final product(s) of basic hydrolysis followed by acidification of ethyl butanoate is _______
- a)ethanoic acid
- b)butanoic acid
- c)ethanoic acid and butanoic acid
- d)butanoic acid and ethanol
Correct answer is option 'B'. Can you explain this answer?
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The final product(s) of basic hydrolysis followed by acidification of ...
Basic Hydrolysis of Ethyl Butanoate
- Basic hydrolysis of ethyl butanoate involves the reaction of ethyl butanoate with a strong base (such as NaOH) in the presence of water to form the corresponding carboxylic acid (butanoic acid) and alcohol (ethanol)
- The reaction can be represented as follows:
Ethyl butanoate + NaOH + H2O → Butanoic acid + Ethanol + NaOH
Acidification of the Mixture
- After the basic hydrolysis, the mixture contains butanoic acid and ethanol along with the salt of the strong base used (NaOH)
- To isolate the butanoic acid and ethanol, the mixture is acidified by adding an acid (such as HCl) to neutralize the base and convert the salt back to the original base
- The acidification can be represented as follows:
NaOH + HCl → NaCl + H2O
Final Product(s)
- The final product of the basic hydrolysis followed by acidification of ethyl butanoate is butanoic acid
- Ethanol is also produced in the hydrolysis step, but it remains in the mixture and is not isolated as a separate product
- The acidification step only serves to neutralize the base used in the hydrolysis and does not affect the products formed in the hydrolysis step
- Basic hydrolysis of ethyl butanoate involves the reaction of ethyl butanoate with a strong base (such as NaOH) in the presence of water to form the corresponding carboxylic acid (butanoic acid) and alcohol (ethanol)
- The reaction can be represented as follows:
Ethyl butanoate + NaOH + H2O → Butanoic acid + Ethanol + NaOH
Acidification of the Mixture
- After the basic hydrolysis, the mixture contains butanoic acid and ethanol along with the salt of the strong base used (NaOH)
- To isolate the butanoic acid and ethanol, the mixture is acidified by adding an acid (such as HCl) to neutralize the base and convert the salt back to the original base
- The acidification can be represented as follows:
NaOH + HCl → NaCl + H2O
Final Product(s)
- The final product of the basic hydrolysis followed by acidification of ethyl butanoate is butanoic acid
- Ethanol is also produced in the hydrolysis step, but it remains in the mixture and is not isolated as a separate product
- The acidification step only serves to neutralize the base used in the hydrolysis and does not affect the products formed in the hydrolysis step
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The final product(s) of basic hydrolysis followed by acidification of ...
Ethyl butanoate (CH3CH2CH2COOC2H5) on basic hydrolysis forms CH3CH2CH2COONa and ethanol. Then this sodium carboxylate compound gets acidified to give butanoic acid.
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The final product(s) of basic hydrolysis followed by acidification of ethyl butanoate is _______a)ethanoic acidb)butanoic acidc)ethanoic acid and butanoic acidd)butanoic acid and ethanolCorrect answer is option 'B'. Can you explain this answer?
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The final product(s) of basic hydrolysis followed by acidification of ethyl butanoate is _______a)ethanoic acidb)butanoic acidc)ethanoic acid and butanoic acidd)butanoic acid and ethanolCorrect answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The final product(s) of basic hydrolysis followed by acidification of ethyl butanoate is _______a)ethanoic acidb)butanoic acidc)ethanoic acid and butanoic acidd)butanoic acid and ethanolCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The final product(s) of basic hydrolysis followed by acidification of ethyl butanoate is _______a)ethanoic acidb)butanoic acidc)ethanoic acid and butanoic acidd)butanoic acid and ethanolCorrect answer is option 'B'. Can you explain this answer?.
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