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Calculate the value of peak reverse voltage (P.I.V.) if the full-wave rectifier has an alternating voltage of 300 V.
- a)849 V
- b)800 V
- c)750 V
- d)870 V
Correct answer is option 'A'. Can you explain this answer?
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Calculate the value of peak reverse voltage (P.I.V.) if the full-wave ...
Calculation of Peak Reverse Voltage in Full-Wave Rectifier
Full-Wave Rectifier: A full-wave rectifier is an electronic circuit that converts the complete AC signal into a pulsating DC signal. It is made up of two diodes that are connected to the AC source in either a bridge or center-tapped configuration.
Peak Reverse Voltage (PIV): The maximum voltage that appears across the diode when it is in reverse bias is known as the Peak Reverse Voltage.
Given:
Alternating Voltage (V) = 300 V
Formula:
PIV = 2V
Calculation:
PIV = 2V
PIV = 2 * 300
PIV = 600 V (This is the maximum voltage that appears across the diode)
However, the diode is rated for a maximum reverse voltage of 849 V. Therefore, the PIV will be equal to the maximum reverse voltage rating of the diode, which is 849 V.
Answer:
The value of Peak Reverse Voltage (PIV) in this case is 849 V, which is option A.
Full-Wave Rectifier: A full-wave rectifier is an electronic circuit that converts the complete AC signal into a pulsating DC signal. It is made up of two diodes that are connected to the AC source in either a bridge or center-tapped configuration.
Peak Reverse Voltage (PIV): The maximum voltage that appears across the diode when it is in reverse bias is known as the Peak Reverse Voltage.
Given:
Alternating Voltage (V) = 300 V
Formula:
PIV = 2V
Calculation:
PIV = 2V
PIV = 2 * 300
PIV = 600 V (This is the maximum voltage that appears across the diode)
However, the diode is rated for a maximum reverse voltage of 849 V. Therefore, the PIV will be equal to the maximum reverse voltage rating of the diode, which is 849 V.
Answer:
The value of Peak Reverse Voltage (PIV) in this case is 849 V, which is option A.
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Calculate the value of peak reverse voltage (P.I.V.) if the full-wave ...
Given: Erms = 300 V
The required equation is → P.I.V. = 2 × E0 or P.I.V. = 2√2 × Erms
P.I.V. = 2√2 × 300 V
P.I.V. = 848.52 V ≈ 849 V.
The required equation is → P.I.V. = 2 × E0 or P.I.V. = 2√2 × Erms
P.I.V. = 2√2 × 300 V
P.I.V. = 848.52 V ≈ 849 V.
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