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A set up is such that there are three similar resistors, each of 20 ohms resistance. Two of them are connected in parallel, and this combination is connected in series with the third one. The maximum power that can be consumed by each resistor is 30 W. Then, what is the maximum power that can be consumed by the combination of all three resistors?
- a)30
- b)20
- c)35
- d)45
Correct answer is option 'D'. Can you explain this answer?
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Most Upvoted Answer
A set up is such that there are three similar resistors, each of 20 oh...
Given:
Three similar resistors of 20 ohms resistance.
Two of them are connected in parallel and this combination is connected in series with the third one.
Maximum power that can be consumed by each resistor is 30 W.
To find: Maximum power that can be consumed by the combination of all three resistors.
Solution:
Let's first calculate the equivalent resistance of the two resistors connected in parallel.
Using the formula:
1/Req = 1/R1 + 1/R2
where R1 = R2 = 20 ohms
1/Req = 1/20 + 1/20
1/Req = 1/10
Req = 10 ohms
Now, the equivalent resistance of the two resistors in parallel is 10 ohms.
Let's calculate the total resistance of the circuit.
The two resistors in parallel and the third resistor in series are connected as follows:
-|----|----|-
| R1 | R2 |
-|----|----|-
|
R3
-|--------|-
The total resistance (Rtotal) can be calculated as:
Rtotal = Req + R3
Rtotal = 10 + 20
Rtotal = 30 ohms
The maximum power that can be consumed by each resistor is given as 30 W.
Since all three resistors are identical, they can consume the same amount of power.
So, the maximum power that can be consumed by the combination of all three resistors is:
Ptotal = P1 + P2 + P3
Ptotal = 30 + 30 + 30
Ptotal = 90 W
Therefore, the maximum power that can be consumed by the combination of all three resistors is 90 W, which is option (d).
Three similar resistors of 20 ohms resistance.
Two of them are connected in parallel and this combination is connected in series with the third one.
Maximum power that can be consumed by each resistor is 30 W.
To find: Maximum power that can be consumed by the combination of all three resistors.
Solution:
Let's first calculate the equivalent resistance of the two resistors connected in parallel.
Using the formula:
1/Req = 1/R1 + 1/R2
where R1 = R2 = 20 ohms
1/Req = 1/20 + 1/20
1/Req = 1/10
Req = 10 ohms
Now, the equivalent resistance of the two resistors in parallel is 10 ohms.
Let's calculate the total resistance of the circuit.
The two resistors in parallel and the third resistor in series are connected as follows:
-|----|----|-
| R1 | R2 |
-|----|----|-
|
R3
-|--------|-
The total resistance (Rtotal) can be calculated as:
Rtotal = Req + R3
Rtotal = 10 + 20
Rtotal = 30 ohms
The maximum power that can be consumed by each resistor is given as 30 W.
Since all three resistors are identical, they can consume the same amount of power.
So, the maximum power that can be consumed by the combination of all three resistors is:
Ptotal = P1 + P2 + P3
Ptotal = 30 + 30 + 30
Ptotal = 90 W
Therefore, the maximum power that can be consumed by the combination of all three resistors is 90 W, which is option (d).
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Community Answer
A set up is such that there are three similar resistors, each of 20 oh...
The equivalent overall resistance of the parallel combination is:
R1 is in series with R2; So, R3 = R1 + R2 = 10 + 20 = 30 ohms.
Now, we can employ the method of cross-multiplication:
For 20 ohms resistor → 30 W power consumed
For 30 ohms resistor combination → x
20x = 30 × 30
x = (30 × 30)/20
x = 45
Therefore, the power consumed by the parallel combination is 45 ohms.
R1 is in series with R2; So, R3 = R1 + R2 = 10 + 20 = 30 ohms.
Now, we can employ the method of cross-multiplication:
For 20 ohms resistor → 30 W power consumed
For 30 ohms resistor combination → x
20x = 30 × 30
x = (30 × 30)/20
x = 45
Therefore, the power consumed by the parallel combination is 45 ohms.
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A set up is such that there are three similar resistors, each of 20 ohms resistance. Two of them are connected in parallel, and this combination is connected in series with the third one. The maximum power that can be consumed by each resistor is 30 W. Then, what is the maximum power that can be consumed by the combination of all three resistors?a)30b)20c)35d)45Correct answer is option 'D'. Can you explain this answer?
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A set up is such that there are three similar resistors, each of 20 ohms resistance. Two of them are connected in parallel, and this combination is connected in series with the third one. The maximum power that can be consumed by each resistor is 30 W. Then, what is the maximum power that can be consumed by the combination of all three resistors?a)30b)20c)35d)45Correct answer is option 'D'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A set up is such that there are three similar resistors, each of 20 ohms resistance. Two of them are connected in parallel, and this combination is connected in series with the third one. The maximum power that can be consumed by each resistor is 30 W. Then, what is the maximum power that can be consumed by the combination of all three resistors?a)30b)20c)35d)45Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A set up is such that there are three similar resistors, each of 20 ohms resistance. Two of them are connected in parallel, and this combination is connected in series with the third one. The maximum power that can be consumed by each resistor is 30 W. Then, what is the maximum power that can be consumed by the combination of all three resistors?a)30b)20c)35d)45Correct answer is option 'D'. Can you explain this answer?.
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