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Electric field intensity at the center of a square is _____ if +20 esu charges are placed at each corner of the square having side-length as 10 cm.
- a)0
- b)0.4 dyne/esu
- c)2 dyne/esu
- d)1.6 dyne/esu
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Electric field intensity at the center of a square is _____ if +20 esu...
Solution:
Given, charges at each corner of the square = 20 esu
Side length of the square = 10 cm
Electric field intensity at the center of the square is to be found.
Let's consider a square with side length 20 cm such that the given square is one of its four quadrants, as shown below:
Charge in each quadrant = 20 esu
Charge in the entire square = 4 × 20 esu = 80 esu
Distance of the center of the square from any corner = side length / √2 = 10 / √2 cm
By symmetry, the electric field due to the charges in each quadrant at the center of the square will be equal in magnitude and direction, and they will cancel out each other. Therefore, the net electric field at the center of the square will be zero.
Hence, the correct option is A) 0.
Given, charges at each corner of the square = 20 esu
Side length of the square = 10 cm
Electric field intensity at the center of the square is to be found.
Let's consider a square with side length 20 cm such that the given square is one of its four quadrants, as shown below:
Charge in each quadrant = 20 esu
Charge in the entire square = 4 × 20 esu = 80 esu
Distance of the center of the square from any corner = side length / √2 = 10 / √2 cm
By symmetry, the electric field due to the charges in each quadrant at the center of the square will be equal in magnitude and direction, and they will cancel out each other. Therefore, the net electric field at the center of the square will be zero.
Hence, the correct option is A) 0.
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Community Answer
Electric field intensity at the center of a square is _____ if +20 esu...
Distance of center from each corner point of the square is = 
Therefore field intensity at the center due to a single charge is = 
dyne/esu. But the fields due to the four charges are equal and are at perpendicular to each other. So the fields balance each other and the net electric field at the center will be equal to zero.
Therefore field intensity at the center due to a single charge is = dyne/esu. But the fields due to the four charges are equal and are at perpendicular to each other. So the fields balance each other and the net electric field at the center will be equal to zero.
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Electric field intensity at the center of a square is _____ if +20 esu charges are placed at each corner of the square having side-length as 10 cm.a)0b)0.4 dyne/esuc)2 dyne/esud)1.6 dyne/esuCorrect answer is option 'A'. Can you explain this answer?
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