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 equals ______
  • a)
    log|x|–(1/2)log(x2+1) + C
  • b)
    log|x|+(1/2)log(x2+1)  + C
  • c)
    –log|x|+(1/2)log(x2+1)  + C
  • d)
    (1/2)log|x|+log(x2+1)  + C
Correct answer is option 'A'. Can you explain this answer?
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equals ______a)log|x|–(1/2)log(x2+1) + Cb)log|x|+(1/2)log(x2+1) ...
We know that 
By simplifying it we get, 
Now equating the coefficients we get A = 0, B = 0, C=1.

Therefore after integrating we get log|x|– (1/2)log(x2+1)  + C.
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equals ______a)log|x|–(1/2)log(x2+1) + Cb)log|x|+(1/2)log(x2+1) + Cc)–log|x|+(1/2)log(x2+1) + Cd)(1/2)log|x|+log(x2+1) + CCorrect answer is option 'A'. Can you explain this answer?
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