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How is the M-C pi bond formed?
  • a)
    Donation of electron pair of half-filled metal d orbital to empty bonding pi orbital of CO
  • b)
    Donation of electron pair of filled metal d orbital to empty bonding pi orbital of CO
  • c)
    Donation of electron pair of filled metal d orbital to empty antibonding pi orbital of CO
  • d)
    Donation of electron pair of half-filled metal d orbital to empty antibonding pi orbital of CO
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
How is the M-C pi bond formed?a)Donation of electron pair of half-fill...
The pi bond involves donation of electrons from filled metal d orbitals into empty antibonding pi orbitals of CO. This is also called a back bond.
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Community Answer
How is the M-C pi bond formed?a)Donation of electron pair of half-fill...
The correct answer is option 'c', which states that the M-C pi bond is formed through the donation of an electron pair from a filled metal d orbital to an empty antibonding pi orbital of CO.

Explanation:
In order to understand the formation of the M-C pi bond, we need to consider the electronic structure of both the metal and the CO ligand.

1. Metal:
Transition metals have partially filled d orbitals, which can participate in bonding with ligands. These d orbitals can donate electron density to the ligand orbitals, forming coordination bonds.

2. Carbon Monoxide (CO) Ligand:
CO is a ligand that can form a pi bond with a metal. The carbon atom in CO has a triple bond with the oxygen atom, consisting of one sigma bond and two pi bonds. The pi bonds are formed by the overlap of the carbon 2p orbital and the oxygen 2p orbitals.

Now, let's consider the formation of the M-C pi bond:

1. Metal d orbital:
The metal has partially filled d orbitals, which can donate electron density to the ligand. In this case, the metal d orbital that participates in the bond formation is a filled orbital.

2. CO pi orbital:
The CO ligand has two pi orbitals, one bonding and one antibonding. The bonding pi orbital is lower in energy and can accept electron density for bond formation. The antibonding pi orbital is higher in energy and cannot participate in bond formation.

3. Donation of electron pair:
The filled metal d orbital donates an electron pair to the empty antibonding pi orbital of CO. This leads to the formation of a coordinate pi bond between the metal and the CO ligand.

Importance of option 'c':
Option 'c' correctly states that the M-C pi bond is formed through the donation of an electron pair from a filled metal d orbital to an empty antibonding pi orbital of CO. This explanation is in line with the concept of pi bonding and the electronic structure of both the metal and the ligand.
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How is the M-C pi bond formed?a)Donation of electron pair of half-filled metal d orbital to empty bonding pi orbital of COb)Donation of electron pair of filled metal d orbital to empty bonding pi orbital of COc)Donation of electron pair of filled metal d orbital to empty antibonding pi orbital of COd)Donation of electron pair of half-filled metal d orbital to empty antibonding pi orbital of COCorrect answer is option 'C'. Can you explain this answer?
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