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A rectangular coil, of sides 4 cm and 5 cm respectively, has 50 turns in it. It carries a current of 2 A, and is placed in a uniform magnetic field of 0.5 T in such a manner that its plane makes an angle of 60o with the field direction. Calculate the torque on the loop.
- a)5 × 10-4 N m
- b)5 × 10-2 N m
- c)5 × 10-3 N m
- d)5 × 10-5 N m
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
A rectangular coil, of sides 4 cm and 5 cm respectively, has 50 turns ...
The magnitude of torque experienced by a current carrying coil kept in a uniform magnetic field is given by:
τ = MB sin (θ) = (NIA) × B sin (θ)
M → Magnetic moment of the coil
N → Number of turns
I → Current in coil
A → Area of the coil
θ → Angle between normal to the plane of the coil and the direction of the magnetic field
Given: N = 50; A = 4 × 5 = 20 cm2 = 20 × 10-4 m2; B = 0.5 T; I = 2 A
θ = 90o – 60o = 30o
τ = (NIA) × B sin (θ)
τ = 50 × 2 × 0.5 × 20 × 10-4 × sin (30o)
τ = 0.05
τ = 5 × 10-2 N m
τ = MB sin (θ) = (NIA) × B sin (θ)
M → Magnetic moment of the coil
N → Number of turns
I → Current in coil
A → Area of the coil
θ → Angle between normal to the plane of the coil and the direction of the magnetic field
Given: N = 50; A = 4 × 5 = 20 cm2 = 20 × 10-4 m2; B = 0.5 T; I = 2 A
θ = 90o – 60o = 30o
τ = (NIA) × B sin (θ)
τ = 50 × 2 × 0.5 × 20 × 10-4 × sin (30o)
τ = 0.05
τ = 5 × 10-2 N m
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A rectangular coil, of sides 4 cm and 5 cm respectively, has 50 turns ...
To calculate the torque on the loop, we can use the formula:
Torque = N * A * B * sin(theta)
Where:
N = number of turns in the loop = 50
A = area of the loop = length * width = 4 cm * 5 cm = 20 cm^2 = 0.002 m^2
B = magnetic field strength = 0.5 T
theta = angle between the loop's plane and the magnetic field direction = 60 degrees
Converting the area to square meters, we have:
A = 0.002 m^2
Substituting the values into the formula:
Torque = 50 * 0.002 m^2 * 0.5 T * sin(60 degrees)
Calculating the torque:
Torque = 50 * 0.002 m^2 * 0.5 T * sin(60 degrees)
Torque = 0.05 Nm * 0.5 * 0.866
Torque = 0.02175 Nm
Therefore, the torque on the loop is approximately 0.02175 Nm.
Torque = N * A * B * sin(theta)
Where:
N = number of turns in the loop = 50
A = area of the loop = length * width = 4 cm * 5 cm = 20 cm^2 = 0.002 m^2
B = magnetic field strength = 0.5 T
theta = angle between the loop's plane and the magnetic field direction = 60 degrees
Converting the area to square meters, we have:
A = 0.002 m^2
Substituting the values into the formula:
Torque = 50 * 0.002 m^2 * 0.5 T * sin(60 degrees)
Calculating the torque:
Torque = 50 * 0.002 m^2 * 0.5 T * sin(60 degrees)
Torque = 0.05 Nm * 0.5 * 0.866
Torque = 0.02175 Nm
Therefore, the torque on the loop is approximately 0.02175 Nm.
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A rectangular coil, of sides 4 cm and 5 cm respectively, has 50 turns in it. It carries a current of 2 A, and is placed in a uniform magnetic field of 0.5 T in such a manner that its plane makes an angle of 60o with the field direction. Calculate the torque on the loop.a)5 × 10-4N mb)5 × 10-2N mc)5 × 10-3N md)5 × 10-5N mCorrect answer is option 'B'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A rectangular coil, of sides 4 cm and 5 cm respectively, has 50 turns in it. It carries a current of 2 A, and is placed in a uniform magnetic field of 0.5 T in such a manner that its plane makes an angle of 60o with the field direction. Calculate the torque on the loop.a)5 × 10-4N mb)5 × 10-2N mc)5 × 10-3N md)5 × 10-5N mCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A rectangular coil, of sides 4 cm and 5 cm respectively, has 50 turns in it. It carries a current of 2 A, and is placed in a uniform magnetic field of 0.5 T in such a manner that its plane makes an angle of 60o with the field direction. Calculate the torque on the loop.a)5 × 10-4N mb)5 × 10-2N mc)5 × 10-3N md)5 × 10-5N mCorrect answer is option 'B'. Can you explain this answer?.
A rectangular coil, of sides 4 cm and 5 cm respectively, has 50 turns in it. It carries a current of 2 A, and is placed in a uniform magnetic field of 0.5 T in such a manner that its plane makes an angle of 60o with the field direction. Calculate the torque on the loop.a)5 × 10-4N mb)5 × 10-2N mc)5 × 10-3N md)5 × 10-5N mCorrect answer is option 'B'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A rectangular coil, of sides 4 cm and 5 cm respectively, has 50 turns in it. It carries a current of 2 A, and is placed in a uniform magnetic field of 0.5 T in such a manner that its plane makes an angle of 60o with the field direction. Calculate the torque on the loop.a)5 × 10-4N mb)5 × 10-2N mc)5 × 10-3N md)5 × 10-5N mCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A rectangular coil, of sides 4 cm and 5 cm respectively, has 50 turns in it. It carries a current of 2 A, and is placed in a uniform magnetic field of 0.5 T in such a manner that its plane makes an angle of 60o with the field direction. Calculate the torque on the loop.a)5 × 10-4N mb)5 × 10-2N mc)5 × 10-3N md)5 × 10-5N mCorrect answer is option 'B'. Can you explain this answer?.
Solutions for A rectangular coil, of sides 4 cm and 5 cm respectively, has 50 turns in it. It carries a current of 2 A, and is placed in a uniform magnetic field of 0.5 T in such a manner that its plane makes an angle of 60o with the field direction. Calculate the torque on the loop.a)5 × 10-4N mb)5 × 10-2N mc)5 × 10-3N md)5 × 10-5N mCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
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ample number of questions to practice A rectangular coil, of sides 4 cm and 5 cm respectively, has 50 turns in it. It carries a current of 2 A, and is placed in a uniform magnetic field of 0.5 T in such a manner that its plane makes an angle of 60o with the field direction. Calculate the torque on the loop.a)5 × 10-4N mb)5 × 10-2N mc)5 × 10-3N md)5 × 10-5N mCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Class 12 tests.
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