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Consider a rope fixed at both ends under tension so that it is horizontal (i.e., assume the rope is along the x-axis, with gravity acting along the z-axis). Now the right end is continually oscillated at high frequency n (say n=100 Hz) horizontally and in a direction along the rope; amplitude of oscillation is negligible. The oscillation travels along the rope and is reflected at the left end.
Let the total length of rope be I, total mass be m and the acceleration due to gravity be g.
After initial phase (say a minute or so), the rope has (BLANK-1)_ wave, which is_(BLANK-2)__in nature. It results from superposition of left travelling and right traveling _(BLANK-3) waves. This resulting wave has a frequency__(BLANK-4) _ that of oscillation frequency nu, Simpy&fmensional analysis indicates that the frequency of can be of the form:___(BLANK-5)__.
- a)stationary, transverse, regular, equal to, sqrt (g/l)
- b)stationary, , regular, equal to, sqrt (g/l), transverse
- c)transverse, regular, equal to, sqrt (g/l), stationary
- d)stationary, regular, sqrt (g/l), transverse, equal to
- e)stationary, sqrt (g/l), transverse, equal to, regular
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
Consider a rope fixed at both ends under tension so that it is horizon...
Answer:
1. Nature of the resulting wave
The resulting wave on the rope after the initial phase is a transverse wave.
2. Frequency of the resulting wave
The frequency of the resulting wave is equal to the oscillation frequency n.
3. Superposition of waves
The resulting wave is formed due to the superposition of left traveling and right traveling waves.
4. Form of the frequency of the resulting wave
The frequency of the resulting wave can be expressed in the form:
(sqrt(g/l))
Explanation:
Let's analyze the given scenario step by step to understand the nature of the wave and its frequency.
1. As the right end of the rope is oscillated horizontally at a high frequency n, a wave is generated that travels along the rope. This wave can be considered as a right traveling wave.
2. When this wave reaches the left end of the rope, it gets reflected. The reflected wave can be considered as a left traveling wave.
3. The resulting wave on the rope is formed due to the superposition of the left and right traveling waves. Since the rope is fixed at both ends, the resulting wave is a standing wave.
4. The standing wave on the rope has a frequency that is equal to the oscillation frequency n. This means that the frequency of the resulting wave is equal to the frequency of the oscillation applied at the right end of the rope.
5. Dimensional analysis suggests that the frequency of the resulting wave can be expressed in terms of the acceleration due to gravity (g) and the length of the rope (l). The only combination that gives a frequency is sqrt(g/l).
Therefore, the answer is: stationary, transverse, regular, equal to, sqrt (g/l)
1. Nature of the resulting wave
The resulting wave on the rope after the initial phase is a transverse wave.
2. Frequency of the resulting wave
The frequency of the resulting wave is equal to the oscillation frequency n.
3. Superposition of waves
The resulting wave is formed due to the superposition of left traveling and right traveling waves.
4. Form of the frequency of the resulting wave
The frequency of the resulting wave can be expressed in the form:
(sqrt(g/l))
Explanation:
Let's analyze the given scenario step by step to understand the nature of the wave and its frequency.
1. As the right end of the rope is oscillated horizontally at a high frequency n, a wave is generated that travels along the rope. This wave can be considered as a right traveling wave.
2. When this wave reaches the left end of the rope, it gets reflected. The reflected wave can be considered as a left traveling wave.
3. The resulting wave on the rope is formed due to the superposition of the left and right traveling waves. Since the rope is fixed at both ends, the resulting wave is a standing wave.
4. The standing wave on the rope has a frequency that is equal to the oscillation frequency n. This means that the frequency of the resulting wave is equal to the frequency of the oscillation applied at the right end of the rope.
5. Dimensional analysis suggests that the frequency of the resulting wave can be expressed in terms of the acceleration due to gravity (g) and the length of the rope (l). The only combination that gives a frequency is sqrt(g/l).
Therefore, the answer is: stationary, transverse, regular, equal to, sqrt (g/l)
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Community Answer
Consider a rope fixed at both ends under tension so that it is horizon...
1. J
2. sinusoidal
3. transverse
4. equal to
2. sinusoidal
3. transverse
4. equal to
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Consider a rope fixed at both ends under tension so that it is horizontal (i.e., assume the rope is along the x-axis, with gravity acting along the z-axis). Now the right end is continually oscillated at high frequency n (say n=100 Hz) horizontally and in a direction along the rope; amplitude of oscillation is negligible. The oscillation travels along the rope and is reflected at the left end.Let the total length of rope be I, total mass be m and the acceleration due to gravity be g.After initial phase (say a minute or so), the rope has (BLANK-1)_ wave, which is_(BLANK-2)__in nature. It results from superposition of left travelling and right traveling _(BLANK-3) waves. This resulting wave has a frequency__(BLANK-4) _ that of oscillation frequency nu, Simpy&fmensional analysis indicates that the frequency of can be of the form:___(BLANK-5)__.a)stationary, transverse, regular, equal to, sqrt (g/l)b)stationary, , regular, equal to, sqrt (g/l),transversec)transverse, regular, equal to, sqrt (g/l),stationaryd)stationary, regular, sqrt (g/l),transverse,equal toe)stationary,sqrt (g/l),transverse,equal to, regularCorrect answer is option 'A'. Can you explain this answer?
Question Description
Consider a rope fixed at both ends under tension so that it is horizontal (i.e., assume the rope is along the x-axis, with gravity acting along the z-axis). Now the right end is continually oscillated at high frequency n (say n=100 Hz) horizontally and in a direction along the rope; amplitude of oscillation is negligible. The oscillation travels along the rope and is reflected at the left end.Let the total length of rope be I, total mass be m and the acceleration due to gravity be g.After initial phase (say a minute or so), the rope has (BLANK-1)_ wave, which is_(BLANK-2)__in nature. It results from superposition of left travelling and right traveling _(BLANK-3) waves. This resulting wave has a frequency__(BLANK-4) _ that of oscillation frequency nu, Simpy&fmensional analysis indicates that the frequency of can be of the form:___(BLANK-5)__.a)stationary, transverse, regular, equal to, sqrt (g/l)b)stationary, , regular, equal to, sqrt (g/l),transversec)transverse, regular, equal to, sqrt (g/l),stationaryd)stationary, regular, sqrt (g/l),transverse,equal toe)stationary,sqrt (g/l),transverse,equal to, regularCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Consider a rope fixed at both ends under tension so that it is horizontal (i.e., assume the rope is along the x-axis, with gravity acting along the z-axis). Now the right end is continually oscillated at high frequency n (say n=100 Hz) horizontally and in a direction along the rope; amplitude of oscillation is negligible. The oscillation travels along the rope and is reflected at the left end.Let the total length of rope be I, total mass be m and the acceleration due to gravity be g.After initial phase (say a minute or so), the rope has (BLANK-1)_ wave, which is_(BLANK-2)__in nature. It results from superposition of left travelling and right traveling _(BLANK-3) waves. This resulting wave has a frequency__(BLANK-4) _ that of oscillation frequency nu, Simpy&fmensional analysis indicates that the frequency of can be of the form:___(BLANK-5)__.a)stationary, transverse, regular, equal to, sqrt (g/l)b)stationary, , regular, equal to, sqrt (g/l),transversec)transverse, regular, equal to, sqrt (g/l),stationaryd)stationary, regular, sqrt (g/l),transverse,equal toe)stationary,sqrt (g/l),transverse,equal to, regularCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider a rope fixed at both ends under tension so that it is horizontal (i.e., assume the rope is along the x-axis, with gravity acting along the z-axis). Now the right end is continually oscillated at high frequency n (say n=100 Hz) horizontally and in a direction along the rope; amplitude of oscillation is negligible. The oscillation travels along the rope and is reflected at the left end.Let the total length of rope be I, total mass be m and the acceleration due to gravity be g.After initial phase (say a minute or so), the rope has (BLANK-1)_ wave, which is_(BLANK-2)__in nature. It results from superposition of left travelling and right traveling _(BLANK-3) waves. This resulting wave has a frequency__(BLANK-4) _ that of oscillation frequency nu, Simpy&fmensional analysis indicates that the frequency of can be of the form:___(BLANK-5)__.a)stationary, transverse, regular, equal to, sqrt (g/l)b)stationary, , regular, equal to, sqrt (g/l),transversec)transverse, regular, equal to, sqrt (g/l),stationaryd)stationary, regular, sqrt (g/l),transverse,equal toe)stationary,sqrt (g/l),transverse,equal to, regularCorrect answer is option 'A'. Can you explain this answer?.
Consider a rope fixed at both ends under tension so that it is horizontal (i.e., assume the rope is along the x-axis, with gravity acting along the z-axis). Now the right end is continually oscillated at high frequency n (say n=100 Hz) horizontally and in a direction along the rope; amplitude of oscillation is negligible. The oscillation travels along the rope and is reflected at the left end.Let the total length of rope be I, total mass be m and the acceleration due to gravity be g.After initial phase (say a minute or so), the rope has (BLANK-1)_ wave, which is_(BLANK-2)__in nature. It results from superposition of left travelling and right traveling _(BLANK-3) waves. This resulting wave has a frequency__(BLANK-4) _ that of oscillation frequency nu, Simpy&fmensional analysis indicates that the frequency of can be of the form:___(BLANK-5)__.a)stationary, transverse, regular, equal to, sqrt (g/l)b)stationary, , regular, equal to, sqrt (g/l),transversec)transverse, regular, equal to, sqrt (g/l),stationaryd)stationary, regular, sqrt (g/l),transverse,equal toe)stationary,sqrt (g/l),transverse,equal to, regularCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Consider a rope fixed at both ends under tension so that it is horizontal (i.e., assume the rope is along the x-axis, with gravity acting along the z-axis). Now the right end is continually oscillated at high frequency n (say n=100 Hz) horizontally and in a direction along the rope; amplitude of oscillation is negligible. The oscillation travels along the rope and is reflected at the left end.Let the total length of rope be I, total mass be m and the acceleration due to gravity be g.After initial phase (say a minute or so), the rope has (BLANK-1)_ wave, which is_(BLANK-2)__in nature. It results from superposition of left travelling and right traveling _(BLANK-3) waves. This resulting wave has a frequency__(BLANK-4) _ that of oscillation frequency nu, Simpy&fmensional analysis indicates that the frequency of can be of the form:___(BLANK-5)__.a)stationary, transverse, regular, equal to, sqrt (g/l)b)stationary, , regular, equal to, sqrt (g/l),transversec)transverse, regular, equal to, sqrt (g/l),stationaryd)stationary, regular, sqrt (g/l),transverse,equal toe)stationary,sqrt (g/l),transverse,equal to, regularCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider a rope fixed at both ends under tension so that it is horizontal (i.e., assume the rope is along the x-axis, with gravity acting along the z-axis). Now the right end is continually oscillated at high frequency n (say n=100 Hz) horizontally and in a direction along the rope; amplitude of oscillation is negligible. The oscillation travels along the rope and is reflected at the left end.Let the total length of rope be I, total mass be m and the acceleration due to gravity be g.After initial phase (say a minute or so), the rope has (BLANK-1)_ wave, which is_(BLANK-2)__in nature. It results from superposition of left travelling and right traveling _(BLANK-3) waves. This resulting wave has a frequency__(BLANK-4) _ that of oscillation frequency nu, Simpy&fmensional analysis indicates that the frequency of can be of the form:___(BLANK-5)__.a)stationary, transverse, regular, equal to, sqrt (g/l)b)stationary, , regular, equal to, sqrt (g/l),transversec)transverse, regular, equal to, sqrt (g/l),stationaryd)stationary, regular, sqrt (g/l),transverse,equal toe)stationary,sqrt (g/l),transverse,equal to, regularCorrect answer is option 'A'. Can you explain this answer?.
Solutions for Consider a rope fixed at both ends under tension so that it is horizontal (i.e., assume the rope is along the x-axis, with gravity acting along the z-axis). Now the right end is continually oscillated at high frequency n (say n=100 Hz) horizontally and in a direction along the rope; amplitude of oscillation is negligible. The oscillation travels along the rope and is reflected at the left end.Let the total length of rope be I, total mass be m and the acceleration due to gravity be g.After initial phase (say a minute or so), the rope has (BLANK-1)_ wave, which is_(BLANK-2)__in nature. It results from superposition of left travelling and right traveling _(BLANK-3) waves. This resulting wave has a frequency__(BLANK-4) _ that of oscillation frequency nu, Simpy&fmensional analysis indicates that the frequency of can be of the form:___(BLANK-5)__.a)stationary, transverse, regular, equal to, sqrt (g/l)b)stationary, , regular, equal to, sqrt (g/l),transversec)transverse, regular, equal to, sqrt (g/l),stationaryd)stationary, regular, sqrt (g/l),transverse,equal toe)stationary,sqrt (g/l),transverse,equal to, regularCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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Here you can find the meaning of Consider a rope fixed at both ends under tension so that it is horizontal (i.e., assume the rope is along the x-axis, with gravity acting along the z-axis). Now the right end is continually oscillated at high frequency n (say n=100 Hz) horizontally and in a direction along the rope; amplitude of oscillation is negligible. The oscillation travels along the rope and is reflected at the left end.Let the total length of rope be I, total mass be m and the acceleration due to gravity be g.After initial phase (say a minute or so), the rope has (BLANK-1)_ wave, which is_(BLANK-2)__in nature. It results from superposition of left travelling and right traveling _(BLANK-3) waves. This resulting wave has a frequency__(BLANK-4) _ that of oscillation frequency nu, Simpy&fmensional analysis indicates that the frequency of can be of the form:___(BLANK-5)__.a)stationary, transverse, regular, equal to, sqrt (g/l)b)stationary, , regular, equal to, sqrt (g/l),transversec)transverse, regular, equal to, sqrt (g/l),stationaryd)stationary, regular, sqrt (g/l),transverse,equal toe)stationary,sqrt (g/l),transverse,equal to, regularCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Consider a rope fixed at both ends under tension so that it is horizontal (i.e., assume the rope is along the x-axis, with gravity acting along the z-axis). Now the right end is continually oscillated at high frequency n (say n=100 Hz) horizontally and in a direction along the rope; amplitude of oscillation is negligible. The oscillation travels along the rope and is reflected at the left end.Let the total length of rope be I, total mass be m and the acceleration due to gravity be g.After initial phase (say a minute or so), the rope has (BLANK-1)_ wave, which is_(BLANK-2)__in nature. It results from superposition of left travelling and right traveling _(BLANK-3) waves. This resulting wave has a frequency__(BLANK-4) _ that of oscillation frequency nu, Simpy&fmensional analysis indicates that the frequency of can be of the form:___(BLANK-5)__.a)stationary, transverse, regular, equal to, sqrt (g/l)b)stationary, , regular, equal to, sqrt (g/l),transversec)transverse, regular, equal to, sqrt (g/l),stationaryd)stationary, regular, sqrt (g/l),transverse,equal toe)stationary,sqrt (g/l),transverse,equal to, regularCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for Consider a rope fixed at both ends under tension so that it is horizontal (i.e., assume the rope is along the x-axis, with gravity acting along the z-axis). Now the right end is continually oscillated at high frequency n (say n=100 Hz) horizontally and in a direction along the rope; amplitude of oscillation is negligible. The oscillation travels along the rope and is reflected at the left end.Let the total length of rope be I, total mass be m and the acceleration due to gravity be g.After initial phase (say a minute or so), the rope has (BLANK-1)_ wave, which is_(BLANK-2)__in nature. It results from superposition of left travelling and right traveling _(BLANK-3) waves. This resulting wave has a frequency__(BLANK-4) _ that of oscillation frequency nu, Simpy&fmensional analysis indicates that the frequency of can be of the form:___(BLANK-5)__.a)stationary, transverse, regular, equal to, sqrt (g/l)b)stationary, , regular, equal to, sqrt (g/l),transversec)transverse, regular, equal to, sqrt (g/l),stationaryd)stationary, regular, sqrt (g/l),transverse,equal toe)stationary,sqrt (g/l),transverse,equal to, regularCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of Consider a rope fixed at both ends under tension so that it is horizontal (i.e., assume the rope is along the x-axis, with gravity acting along the z-axis). Now the right end is continually oscillated at high frequency n (say n=100 Hz) horizontally and in a direction along the rope; amplitude of oscillation is negligible. The oscillation travels along the rope and is reflected at the left end.Let the total length of rope be I, total mass be m and the acceleration due to gravity be g.After initial phase (say a minute or so), the rope has (BLANK-1)_ wave, which is_(BLANK-2)__in nature. It results from superposition of left travelling and right traveling _(BLANK-3) waves. This resulting wave has a frequency__(BLANK-4) _ that of oscillation frequency nu, Simpy&fmensional analysis indicates that the frequency of can be of the form:___(BLANK-5)__.a)stationary, transverse, regular, equal to, sqrt (g/l)b)stationary, , regular, equal to, sqrt (g/l),transversec)transverse, regular, equal to, sqrt (g/l),stationaryd)stationary, regular, sqrt (g/l),transverse,equal toe)stationary,sqrt (g/l),transverse,equal to, regularCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Consider a rope fixed at both ends under tension so that it is horizontal (i.e., assume the rope is along the x-axis, with gravity acting along the z-axis). Now the right end is continually oscillated at high frequency n (say n=100 Hz) horizontally and in a direction along the rope; amplitude of oscillation is negligible. The oscillation travels along the rope and is reflected at the left end.Let the total length of rope be I, total mass be m and the acceleration due to gravity be g.After initial phase (say a minute or so), the rope has (BLANK-1)_ wave, which is_(BLANK-2)__in nature. It results from superposition of left travelling and right traveling _(BLANK-3) waves. This resulting wave has a frequency__(BLANK-4) _ that of oscillation frequency nu, Simpy&fmensional analysis indicates that the frequency of can be of the form:___(BLANK-5)__.a)stationary, transverse, regular, equal to, sqrt (g/l)b)stationary, , regular, equal to, sqrt (g/l),transversec)transverse, regular, equal to, sqrt (g/l),stationaryd)stationary, regular, sqrt (g/l),transverse,equal toe)stationary,sqrt (g/l),transverse,equal to, regularCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.
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