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A wire is 4m long and has a mass 0.2kg. The wire is kept horizontally. A transverse pulse is generated by plucking one end of the taut (tight) wire. The pulse makes four trips back and worth along the cord in 0.8 sec . The tension in the cord will be- (A) 80 N (B) 160 N (C) 240N (D) 320N.?
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A wire is 4m long and has a mass 0.2kg. The wire is kept horizontally....
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A wire is 4m long and has a mass 0.2kg. The wire is kept horizontally....
Given:
Length of wire (L) = 4m
Mass of wire (m) = 0.2kg
Time taken for four trips (T) = 0.8s
To find:
Tension in the wire
Analysis:
When a pulse is generated in a taut wire, it travels back and forth along the wire. The speed at which the pulse travels is given by the formula:
v = √(T/μ)
Where:
v is the velocity of the pulse,
T is the tension in the wire, and
μ is the linear mass density of the wire.
The linear mass density (μ) is given by the formula:
μ = m/L
Where:
m is the mass of the wire, and
L is the length of the wire.
The time taken for the pulse to travel back and forth along the wire is given by the formula:
T = 2L/v
Where:
T is the time taken,
L is the length of the wire, and
v is the velocity of the pulse.
In this case, we are given the values of L, m, and T. We can use these formulas to find the tension in the wire.
Solution:
Step 1: Calculate the linear mass density (μ)
μ = m/L
= 0.2kg / 4m
= 0.05 kg/m
Step 2: Calculate the velocity of the pulse (v)
v = √(T/μ)
= √(0.8s / 0.05 kg/m)
= √(16 m²/s²)
= 4 m/s
Step 3: Calculate the tension in the wire (T)
T = 2L/v
= 2 * 4m / 4 m/s
= 8 N
Therefore, the tension in the wire is 8 N.
Length of wire (L) = 4m
Mass of wire (m) = 0.2kg
Time taken for four trips (T) = 0.8s
To find:
Tension in the wire
Analysis:
When a pulse is generated in a taut wire, it travels back and forth along the wire. The speed at which the pulse travels is given by the formula:
v = √(T/μ)
Where:
v is the velocity of the pulse,
T is the tension in the wire, and
μ is the linear mass density of the wire.
The linear mass density (μ) is given by the formula:
μ = m/L
Where:
m is the mass of the wire, and
L is the length of the wire.
The time taken for the pulse to travel back and forth along the wire is given by the formula:
T = 2L/v
Where:
T is the time taken,
L is the length of the wire, and
v is the velocity of the pulse.
In this case, we are given the values of L, m, and T. We can use these formulas to find the tension in the wire.
Solution:
Step 1: Calculate the linear mass density (μ)
μ = m/L
= 0.2kg / 4m
= 0.05 kg/m
Step 2: Calculate the velocity of the pulse (v)
v = √(T/μ)
= √(0.8s / 0.05 kg/m)
= √(16 m²/s²)
= 4 m/s
Step 3: Calculate the tension in the wire (T)
T = 2L/v
= 2 * 4m / 4 m/s
= 8 N
Therefore, the tension in the wire is 8 N.
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A wire is 4m long and has a mass 0.2kg. The wire is kept horizontally. A transverse pulse is generated by plucking one end of the taut (tight) wire. The pulse makes four trips back and worth along the cord in 0.8 sec . The tension in the cord will be- (A) 80 N (B) 160 N (C) 240N (D) 320N.?
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A wire is 4m long and has a mass 0.2kg. The wire is kept horizontally. A transverse pulse is generated by plucking one end of the taut (tight) wire. The pulse makes four trips back and worth along the cord in 0.8 sec . The tension in the cord will be- (A) 80 N (B) 160 N (C) 240N (D) 320N.? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A wire is 4m long and has a mass 0.2kg. The wire is kept horizontally. A transverse pulse is generated by plucking one end of the taut (tight) wire. The pulse makes four trips back and worth along the cord in 0.8 sec . The tension in the cord will be- (A) 80 N (B) 160 N (C) 240N (D) 320N.? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A wire is 4m long and has a mass 0.2kg. The wire is kept horizontally. A transverse pulse is generated by plucking one end of the taut (tight) wire. The pulse makes four trips back and worth along the cord in 0.8 sec . The tension in the cord will be- (A) 80 N (B) 160 N (C) 240N (D) 320N.?.
A wire is 4m long and has a mass 0.2kg. The wire is kept horizontally. A transverse pulse is generated by plucking one end of the taut (tight) wire. The pulse makes four trips back and worth along the cord in 0.8 sec . The tension in the cord will be- (A) 80 N (B) 160 N (C) 240N (D) 320N.? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A wire is 4m long and has a mass 0.2kg. The wire is kept horizontally. A transverse pulse is generated by plucking one end of the taut (tight) wire. The pulse makes four trips back and worth along the cord in 0.8 sec . The tension in the cord will be- (A) 80 N (B) 160 N (C) 240N (D) 320N.? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A wire is 4m long and has a mass 0.2kg. The wire is kept horizontally. A transverse pulse is generated by plucking one end of the taut (tight) wire. The pulse makes four trips back and worth along the cord in 0.8 sec . The tension in the cord will be- (A) 80 N (B) 160 N (C) 240N (D) 320N.?.
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