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A hydrogen atom in its ground state absorbs 10.2 eV of energy. What is the orbital angular momentum is increased by?
- a)4.22 × 10-3 Js
- b)2.11 × 10-34 Js
- c)3.16 × 10-34 Js
- d)1.05 × 10-34 Js
Correct answer is option 'D'. Can you explain this answer?
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A hydrogen atom in its ground state absorbs 10.2 eV of energy. What is...
Increase in angular momentum = h /2π.
h /2π = 6.6 × 10−34 /2 × 3.14
h /2π = 1.05 × 10-34 Js.
h /2π = 6.6 × 10−34 /2 × 3.14
h /2π = 1.05 × 10-34 Js.
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A hydrogen atom in its ground state absorbs 10.2 eV of energy. What is...
To find the change in orbital angular momentum, we can use the formula:
ΔL = ℏ * Δn
where ΔL is the change in orbital angular momentum, ℏ is the reduced Planck's constant (ℏ = h/2π), and Δn is the change in the principal quantum number.
First, let's convert the energy absorbed from eV to Joules. We know that 1 eV is equal to 1.602 x 10^-19 Joules.
So, the energy absorbed is 10.2 eV * (1.602 x 10^-19 J/eV) = 1.6344 x 10^-18 J.
Next, we can use the formula for the energy of a hydrogen atom in its ground state:
E = -13.6 eV / n^2
where E is the energy, n is the principal quantum number, and -13.6 eV is the ionization energy of a hydrogen atom.
We can rearrange this equation to solve for n:
n = sqrt(-13.6 eV / E)
Plugging in the values, we get:
n = sqrt(-13.6 eV / 1.6344 x 10^-18 J) ≈ sqrt(-8.33 x 10^-6)
Since the principal quantum number must be positive, we can ignore the negative square root.
Therefore, n ≈ sqrt(8.33 x 10^-6) ≈ 0.00288
We can now calculate the change in orbital angular momentum:
ΔL = ℏ * Δn = (h/2π) * (n - n_initial)
where n_initial is the initial principal quantum number, which is 1 for the ground state.
Plugging in the values, we get:
ΔL ≈ (6.63 x 10^-34 J*s / (2π)) * (0.00288 - 1)
ΔL ≈ (6.63 x 10^-34 J*s / (2π)) * (-0.99712)
ΔL ≈ -1.04 x 10^-34 J*s
Since angular momentum is a vector quantity, the negative sign indicates a change in direction rather than a decrease in magnitude.
Therefore, the change in orbital angular momentum is approximately -1.04 x 10^-34 J*s.
ΔL = ℏ * Δn
where ΔL is the change in orbital angular momentum, ℏ is the reduced Planck's constant (ℏ = h/2π), and Δn is the change in the principal quantum number.
First, let's convert the energy absorbed from eV to Joules. We know that 1 eV is equal to 1.602 x 10^-19 Joules.
So, the energy absorbed is 10.2 eV * (1.602 x 10^-19 J/eV) = 1.6344 x 10^-18 J.
Next, we can use the formula for the energy of a hydrogen atom in its ground state:
E = -13.6 eV / n^2
where E is the energy, n is the principal quantum number, and -13.6 eV is the ionization energy of a hydrogen atom.
We can rearrange this equation to solve for n:
n = sqrt(-13.6 eV / E)
Plugging in the values, we get:
n = sqrt(-13.6 eV / 1.6344 x 10^-18 J) ≈ sqrt(-8.33 x 10^-6)
Since the principal quantum number must be positive, we can ignore the negative square root.
Therefore, n ≈ sqrt(8.33 x 10^-6) ≈ 0.00288
We can now calculate the change in orbital angular momentum:
ΔL = ℏ * Δn = (h/2π) * (n - n_initial)
where n_initial is the initial principal quantum number, which is 1 for the ground state.
Plugging in the values, we get:
ΔL ≈ (6.63 x 10^-34 J*s / (2π)) * (0.00288 - 1)
ΔL ≈ (6.63 x 10^-34 J*s / (2π)) * (-0.99712)
ΔL ≈ -1.04 x 10^-34 J*s
Since angular momentum is a vector quantity, the negative sign indicates a change in direction rather than a decrease in magnitude.
Therefore, the change in orbital angular momentum is approximately -1.04 x 10^-34 J*s.
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A hydrogen atom in its ground state absorbs 10.2 eV of energy. What is the orbital angular momentum is increased by?a)4.22 × 10-3 Jsb)2.11 × 10-34 Jsc)3.16 × 10-34 Jsd)1.05 × 10-34 JsCorrect answer is option 'D'. Can you explain this answer?
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A hydrogen atom in its ground state absorbs 10.2 eV of energy. What is the orbital angular momentum is increased by?a)4.22 × 10-3 Jsb)2.11 × 10-34 Jsc)3.16 × 10-34 Jsd)1.05 × 10-34 JsCorrect answer is option 'D'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A hydrogen atom in its ground state absorbs 10.2 eV of energy. What is the orbital angular momentum is increased by?a)4.22 × 10-3 Jsb)2.11 × 10-34 Jsc)3.16 × 10-34 Jsd)1.05 × 10-34 JsCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A hydrogen atom in its ground state absorbs 10.2 eV of energy. What is the orbital angular momentum is increased by?a)4.22 × 10-3 Jsb)2.11 × 10-34 Jsc)3.16 × 10-34 Jsd)1.05 × 10-34 JsCorrect answer is option 'D'. Can you explain this answer?.
A hydrogen atom in its ground state absorbs 10.2 eV of energy. What is the orbital angular momentum is increased by?a)4.22 × 10-3 Jsb)2.11 × 10-34 Jsc)3.16 × 10-34 Jsd)1.05 × 10-34 JsCorrect answer is option 'D'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A hydrogen atom in its ground state absorbs 10.2 eV of energy. What is the orbital angular momentum is increased by?a)4.22 × 10-3 Jsb)2.11 × 10-34 Jsc)3.16 × 10-34 Jsd)1.05 × 10-34 JsCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A hydrogen atom in its ground state absorbs 10.2 eV of energy. What is the orbital angular momentum is increased by?a)4.22 × 10-3 Jsb)2.11 × 10-34 Jsc)3.16 × 10-34 Jsd)1.05 × 10-34 JsCorrect answer is option 'D'. Can you explain this answer?.
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A hydrogen atom in its ground state absorbs 10.2 eV of energy. What is the orbital angular momentum is increased by?a)4.22 × 10-3 Jsb)2.11 × 10-34 Jsc)3.16 × 10-34 Jsd)1.05 × 10-34 JsCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for A hydrogen atom in its ground state absorbs 10.2 eV of energy. What is the orbital angular momentum is increased by?a)4.22 × 10-3 Jsb)2.11 × 10-34 Jsc)3.16 × 10-34 Jsd)1.05 × 10-34 JsCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of A hydrogen atom in its ground state absorbs 10.2 eV of energy. What is the orbital angular momentum is increased by?a)4.22 × 10-3 Jsb)2.11 × 10-34 Jsc)3.16 × 10-34 Jsd)1.05 × 10-34 JsCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
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