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In a group of students, 1/5 are aged below 8 years. Of the remaining 2/5 are above 8 years. What fraction of the students are exactly 8 years of age?
  • a)
    12/25
  • b)
    2/5
  • c)
    3/5
  • d)
    4/25
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
In a group of students, 1/5 are aged below 8 years. Of the remaining 2...
Given information:
- 1/5 of the students are aged below 8 years.
- 2/5 of the students are above 8 years.
- We need to find the fraction of students who are exactly 8 years old.

Solution:
Let's assume that there are a total of 5x students in the group.
- 1/5 of the students are below 8 years old, which means there are x students below 8 years old.
- 2/5 of the students are above 8 years old, which means there are 2x students above 8 years old.
- The remaining students must be exactly 8 years old, which means there are 5x - x - 2x = 2x students who are exactly 8 years old.

So, the fraction of students who are exactly 8 years old is:
2x / 5x = 2/5

Therefore, the correct answer is option A) 12/25.

Explanation:
We can solve this problem by using fractions and assuming a total number of students. By assuming that there are 5x students in the group, we can easily calculate the number of students in each age group. Finally, we can subtract the number of students in the other two age groups from the total number of students to find the number of students who are exactly 8 years old.
Community Answer
In a group of students, 1/5 are aged below 8 years. Of the remaining 2...
Let the total number of students in the group be 1
Number of students who are below age 8 = 1 × 1/5 = 1/5
Remaining students = 1 – 1/5 = 4/5
Number of students who are above age 8 = 4/5 × 2/5 = 8/25
Number of students who are exactly 8 years old = 1 – 1/5 – 8/25 = 12/25
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In a group of students, 1/5 are aged below 8 years. Of the remaining 2/5 are above 8 years. What fraction of the students are exactly 8 years of age?a)12/25b)2/5c)3/5d)4/25Correct answer is option 'A'. Can you explain this answer?
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