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22. The difference between in simple interest on a sum invested of overline Psi 1500 for 3 years is *18. The difference in their rate is (a) 0.4 (b) 0.6 4/16) 0.8 (d) 0.10?
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22. The difference between in simple interest on a sum invested of ove...
Solution:
Given, Principal (P) = overline Psi 1500, Time (t) = 3 years
Let the two rates be r1 and r2. Then,
Simple Interest (SI) = (P * r1 * t)/100
SI1 - SI2 = (P * r1 * t)/100 - (P * r2 * t)/100
18 = P * t * (r1 - r2)/100
Calculation of rate difference:
We need to find the difference between the two rates. Let's assume that the rate r2 is lesser than r1.
r1 - r2 = (18 * 100)/(P * t)
r1 - r2 = (18 * 100)/(1500 * 3)
r1 - r2 = 0.4
Therefore, the difference in their rate is 0.4.
Explanation:
In this question, we have to find the difference between the two rates when the principal is overline Psi 1500 and invested for 3 years with a difference of 18 in the simple interest earned.
We know that Simple Interest (SI) = (P * r * t)/100
We can find the difference in SI by subtracting the SI of the two rates. Then, we equate the difference in SI to 18 and calculate the rate difference. We assume that the rate r2 is lesser than r1.
Finally, we get the rate difference as 0.4.
Hence, the correct option is (a) 0.4.
Given, Principal (P) = overline Psi 1500, Time (t) = 3 years
Let the two rates be r1 and r2. Then,
Simple Interest (SI) = (P * r1 * t)/100
SI1 - SI2 = (P * r1 * t)/100 - (P * r2 * t)/100
18 = P * t * (r1 - r2)/100
Calculation of rate difference:
We need to find the difference between the two rates. Let's assume that the rate r2 is lesser than r1.
r1 - r2 = (18 * 100)/(P * t)
r1 - r2 = (18 * 100)/(1500 * 3)
r1 - r2 = 0.4
Therefore, the difference in their rate is 0.4.
Explanation:
In this question, we have to find the difference between the two rates when the principal is overline Psi 1500 and invested for 3 years with a difference of 18 in the simple interest earned.
We know that Simple Interest (SI) = (P * r * t)/100
We can find the difference in SI by subtracting the SI of the two rates. Then, we equate the difference in SI to 18 and calculate the rate difference. We assume that the rate r2 is lesser than r1.
Finally, we get the rate difference as 0.4.
Hence, the correct option is (a) 0.4.
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22. The difference between in simple interest on a sum invested of overline Psi 1500 for 3 years is *18. The difference in their rate is (a) 0.4 (b) 0.6 4/16) 0.8 (d) 0.10?
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22. The difference between in simple interest on a sum invested of overline Psi 1500 for 3 years is *18. The difference in their rate is (a) 0.4 (b) 0.6 4/16) 0.8 (d) 0.10? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about 22. The difference between in simple interest on a sum invested of overline Psi 1500 for 3 years is *18. The difference in their rate is (a) 0.4 (b) 0.6 4/16) 0.8 (d) 0.10? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 22. The difference between in simple interest on a sum invested of overline Psi 1500 for 3 years is *18. The difference in their rate is (a) 0.4 (b) 0.6 4/16) 0.8 (d) 0.10?.
22. The difference between in simple interest on a sum invested of overline Psi 1500 for 3 years is *18. The difference in their rate is (a) 0.4 (b) 0.6 4/16) 0.8 (d) 0.10? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about 22. The difference between in simple interest on a sum invested of overline Psi 1500 for 3 years is *18. The difference in their rate is (a) 0.4 (b) 0.6 4/16) 0.8 (d) 0.10? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 22. The difference between in simple interest on a sum invested of overline Psi 1500 for 3 years is *18. The difference in their rate is (a) 0.4 (b) 0.6 4/16) 0.8 (d) 0.10?.
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