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What will be the output of the following C++ code?
#include <iostream>
#include <string>
using namespace std;
class complex
{
int i;
int j;
public:
complex(){}
complex(int a, int b)
{
i = a;
j = b;
}
complex operator+(complex c)
{
complex temp;
temp.i = this->i + c.i;
temp.j = this->j + c.j;
return temp;
}
void show(){
cout<<"Complex Number: "<<i<<" + i"<<j<<endl;
}
};
int main(int argc, char const *argv[])
{
complex c1(1,2);
complex c2(3,4);
complex c3 = c1 + c2;
c3.show();
return 0;
}
#include <string>
using namespace std;
class complex
{
int i;
int j;
public:
complex(){}
complex(int a, int b)
{
i = a;
j = b;
}
complex operator+(complex c)
{
complex temp;
temp.i = this->i + c.i;
temp.j = this->j + c.j;
return temp;
}
void show(){
cout<<"Complex Number: "<<i<<" + i"<<j<<endl;
}
};
int main(int argc, char const *argv[])
{
complex c1(1,2);
complex c2(3,4);
complex c3 = c1 + c2;
c3.show();
return 0;
}
- a)Complex Number: 4 + i6
- b)Complex Number: 2 + i2
- c)Error
- d)Segmentation fault
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
What will be the output of the following C++ code?#include <iostrea...
As we have defined in the class complec that when we add the two objects of the class complex then add those two complex numbers and show() displays that result.
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Community Answer
What will be the output of the following C++ code?#include <iostrea...
Explanation:
- The code defines a class `complex` with two integer data members `i` and `j`.
- It also defines a parameterized constructor and an overloaded `+` operator for adding two complex numbers.
- The `show` method is used to display the complex number in the format `Complex Number: a + ib`.
- In the `main` function, two complex objects `c1` and `c2` are created with values (1, 2) and (3, 4) respectively.
- The `operator+` function is called when `c1 + c2` is performed, resulting in a new complex object `c3` with values (4, 6).
- Finally, the `show` method is called on `c3` to display the sum of the two complex numbers.
Therefore, the output of the code will be:
Output: Complex Number: 4 + i6
- The code defines a class `complex` with two integer data members `i` and `j`.
- It also defines a parameterized constructor and an overloaded `+` operator for adding two complex numbers.
- The `show` method is used to display the complex number in the format `Complex Number: a + ib`.
- In the `main` function, two complex objects `c1` and `c2` are created with values (1, 2) and (3, 4) respectively.
- The `operator+` function is called when `c1 + c2` is performed, resulting in a new complex object `c3` with values (4, 6).
- Finally, the `show` method is called on `c3` to display the sum of the two complex numbers.
Therefore, the output of the code will be:
Output: Complex Number: 4 + i6
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What will be the output of the following C++ code?#include <iostream>#include <string>using namespace std;class complex{ int i; int j; public: complex(){} complex(int a, int b) { i = a; j = b; } complex operator+(complex c) { complex temp; temp.i = this->i + c.i; temp.j = this->j + c.j; return temp; } void show(){ cout<<"Complex Number: "<<i<<" + i"<<j<<endl; }};int main(int argc, char const *argv[]){ complex c1(1,2); complex c2(3,4); complex c3 = c1 + c2; c3.show(); return 0;}a)Complex Number: 4 + i6b)Complex Number: 2 + i2c)Errord)Segmentation faultCorrect answer is option 'A'. Can you explain this answer? for Class 7 2025 is part of Class 7 preparation. The Question and answers have been prepared according to the Class 7 exam syllabus. Information about What will be the output of the following C++ code?#include <iostream>#include <string>using namespace std;class complex{ int i; int j; public: complex(){} complex(int a, int b) { i = a; j = b; } complex operator+(complex c) { complex temp; temp.i = this->i + c.i; temp.j = this->j + c.j; return temp; } void show(){ cout<<"Complex Number: "<<i<<" + i"<<j<<endl; }};int main(int argc, char const *argv[]){ complex c1(1,2); complex c2(3,4); complex c3 = c1 + c2; c3.show(); return 0;}a)Complex Number: 4 + i6b)Complex Number: 2 + i2c)Errord)Segmentation faultCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 7 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What will be the output of the following C++ code?#include <iostream>#include <string>using namespace std;class complex{ int i; int j; public: complex(){} complex(int a, int b) { i = a; j = b; } complex operator+(complex c) { complex temp; temp.i = this->i + c.i; temp.j = this->j + c.j; return temp; } void show(){ cout<<"Complex Number: "<<i<<" + i"<<j<<endl; }};int main(int argc, char const *argv[]){ complex c1(1,2); complex c2(3,4); complex c3 = c1 + c2; c3.show(); return 0;}a)Complex Number: 4 + i6b)Complex Number: 2 + i2c)Errord)Segmentation faultCorrect answer is option 'A'. Can you explain this answer?.
What will be the output of the following C++ code?#include <iostream>#include <string>using namespace std;class complex{ int i; int j; public: complex(){} complex(int a, int b) { i = a; j = b; } complex operator+(complex c) { complex temp; temp.i = this->i + c.i; temp.j = this->j + c.j; return temp; } void show(){ cout<<"Complex Number: "<<i<<" + i"<<j<<endl; }};int main(int argc, char const *argv[]){ complex c1(1,2); complex c2(3,4); complex c3 = c1 + c2; c3.show(); return 0;}a)Complex Number: 4 + i6b)Complex Number: 2 + i2c)Errord)Segmentation faultCorrect answer is option 'A'. Can you explain this answer? for Class 7 2025 is part of Class 7 preparation. The Question and answers have been prepared according to the Class 7 exam syllabus. Information about What will be the output of the following C++ code?#include <iostream>#include <string>using namespace std;class complex{ int i; int j; public: complex(){} complex(int a, int b) { i = a; j = b; } complex operator+(complex c) { complex temp; temp.i = this->i + c.i; temp.j = this->j + c.j; return temp; } void show(){ cout<<"Complex Number: "<<i<<" + i"<<j<<endl; }};int main(int argc, char const *argv[]){ complex c1(1,2); complex c2(3,4); complex c3 = c1 + c2; c3.show(); return 0;}a)Complex Number: 4 + i6b)Complex Number: 2 + i2c)Errord)Segmentation faultCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 7 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What will be the output of the following C++ code?#include <iostream>#include <string>using namespace std;class complex{ int i; int j; public: complex(){} complex(int a, int b) { i = a; j = b; } complex operator+(complex c) { complex temp; temp.i = this->i + c.i; temp.j = this->j + c.j; return temp; } void show(){ cout<<"Complex Number: "<<i<<" + i"<<j<<endl; }};int main(int argc, char const *argv[]){ complex c1(1,2); complex c2(3,4); complex c3 = c1 + c2; c3.show(); return 0;}a)Complex Number: 4 + i6b)Complex Number: 2 + i2c)Errord)Segmentation faultCorrect answer is option 'A'. Can you explain this answer?.
Solutions for What will be the output of the following C++ code?#include <iostream>#include <string>using namespace std;class complex{ int i; int j; public: complex(){} complex(int a, int b) { i = a; j = b; } complex operator+(complex c) { complex temp; temp.i = this->i + c.i; temp.j = this->j + c.j; return temp; } void show(){ cout<<"Complex Number: "<<i<<" + i"<<j<<endl; }};int main(int argc, char const *argv[]){ complex c1(1,2); complex c2(3,4); complex c3 = c1 + c2; c3.show(); return 0;}a)Complex Number: 4 + i6b)Complex Number: 2 + i2c)Errord)Segmentation faultCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 7.
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Here you can find the meaning of What will be the output of the following C++ code?#include <iostream>#include <string>using namespace std;class complex{ int i; int j; public: complex(){} complex(int a, int b) { i = a; j = b; } complex operator+(complex c) { complex temp; temp.i = this->i + c.i; temp.j = this->j + c.j; return temp; } void show(){ cout<<"Complex Number: "<<i<<" + i"<<j<<endl; }};int main(int argc, char const *argv[]){ complex c1(1,2); complex c2(3,4); complex c3 = c1 + c2; c3.show(); return 0;}a)Complex Number: 4 + i6b)Complex Number: 2 + i2c)Errord)Segmentation faultCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
What will be the output of the following C++ code?#include <iostream>#include <string>using namespace std;class complex{ int i; int j; public: complex(){} complex(int a, int b) { i = a; j = b; } complex operator+(complex c) { complex temp; temp.i = this->i + c.i; temp.j = this->j + c.j; return temp; } void show(){ cout<<"Complex Number: "<<i<<" + i"<<j<<endl; }};int main(int argc, char const *argv[]){ complex c1(1,2); complex c2(3,4); complex c3 = c1 + c2; c3.show(); return 0;}a)Complex Number: 4 + i6b)Complex Number: 2 + i2c)Errord)Segmentation faultCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for What will be the output of the following C++ code?#include <iostream>#include <string>using namespace std;class complex{ int i; int j; public: complex(){} complex(int a, int b) { i = a; j = b; } complex operator+(complex c) { complex temp; temp.i = this->i + c.i; temp.j = this->j + c.j; return temp; } void show(){ cout<<"Complex Number: "<<i<<" + i"<<j<<endl; }};int main(int argc, char const *argv[]){ complex c1(1,2); complex c2(3,4); complex c3 = c1 + c2; c3.show(); return 0;}a)Complex Number: 4 + i6b)Complex Number: 2 + i2c)Errord)Segmentation faultCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of What will be the output of the following C++ code?#include <iostream>#include <string>using namespace std;class complex{ int i; int j; public: complex(){} complex(int a, int b) { i = a; j = b; } complex operator+(complex c) { complex temp; temp.i = this->i + c.i; temp.j = this->j + c.j; return temp; } void show(){ cout<<"Complex Number: "<<i<<" + i"<<j<<endl; }};int main(int argc, char const *argv[]){ complex c1(1,2); complex c2(3,4); complex c3 = c1 + c2; c3.show(); return 0;}a)Complex Number: 4 + i6b)Complex Number: 2 + i2c)Errord)Segmentation faultCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice What will be the output of the following C++ code?#include <iostream>#include <string>using namespace std;class complex{ int i; int j; public: complex(){} complex(int a, int b) { i = a; j = b; } complex operator+(complex c) { complex temp; temp.i = this->i + c.i; temp.j = this->j + c.j; return temp; } void show(){ cout<<"Complex Number: "<<i<<" + i"<<j<<endl; }};int main(int argc, char const *argv[]){ complex c1(1,2); complex c2(3,4); complex c3 = c1 + c2; c3.show(); return 0;}a)Complex Number: 4 + i6b)Complex Number: 2 + i2c)Errord)Segmentation faultCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice Class 7 tests.
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