A train passes two persons walking in opposite directions at a speed of 5 m/s and 10 m/s in 6 seconds and 5 seconds respectively. Find the length of the train?a)140 mb)150 mc)160 md)120 mCorrect answer is option 'B'. Can you explain this answer?

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A train passes two persons walking in opposite directions at a speed of 5 m/s and 10 m/s in 6 seconds and 5 seconds respectively. Find the length of the train?

a)
140 m
b)
150 m
c)
160 m
d)
120 m

Correct answer is option 'B'. Can you explain this answer?

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A train passes two persons walking in opposite directions at a speed o...

To find the length of the train, we need to consider the relative speeds and times it takes for the train to pass the two persons walking in opposite directions.

Let's assume the length of the train is 'L' meters.

Given:
Speed of the first person = 5 m/s
Time taken to pass the first person = 6 seconds

Speed of the second person = 10 m/s
Time taken to pass the second person = 5 seconds

Let's calculate the distance covered by the train while passing each person.

Distance covered by the train while passing the first person:
Distance = Speed × Time
Distance = 5 m/s × 6 s
Distance = 30 meters

Distance covered by the train while passing the second person:
Distance = Speed × Time
Distance = 10 m/s × 5 s
Distance = 50 meters

Since the two persons are walking in opposite directions, the total distance covered by the train while passing both persons is the sum of the distances covered while passing each person.

Total distance covered = 30 meters + 50 meters
Total distance covered = 80 meters

Now, we know that the total distance covered by the train is equal to the length of the train.

Therefore, the length of the train is 80 meters.

However, none of the given options match the calculated length. So, there might be an error in the question or options provided.

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A train passes two persons walking in opposite directions at a speed o...

Let the speed of the train be 's' m/s.

Let the length of the train be 'x' meters.

Relative speed of train and the first person who is moving at the speed of 5 m/s in opposite direction = (s+5) m/s.

Therefore, total distance travelled (i.e length of train) 'x'= Relative speed X time

x = (s+5) * 6 …. ( Eq 1)

Relative speed of train and the second person who is moving at the speed of 10 m/s in opposite direction = (s+10) m/s

Therefore, total distance travelled (i.e length of train) 'x' = Relative speed X time

x = (s+10) * 5 …. (Eq 2)

Since length of the train is same in both the cases, if we equate the equation 1 and equation 2 we get

⇒ (s+5) * 6 = (s+10) * 5

⇒ 6s+30= 5s+50

⇒ 6s - 5s = 50 - 30

⇒ s = 20 m/s (i.e speed of the train)

Now, putting the value of speed of the train in equation 1 (we can put the value equation 2 as well) we get

Length of the train 'x' = (20+5) * 6

x = 25 * 6
x= 150

Therefore, length of the train is 150 meters.

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A train passes two persons walking in opposite directions at a speed of 5 m/s and 10 m/s in 6 seconds and 5 seconds respectively. Find the length of the train?a)140 mb)150 mc)160 md)120 mCorrect answer is option 'B'. Can you explain this answer?

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