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What will be the output of the following C++ code?
#include <iostream>
using namespace std;
void square (int *x, int *y)
{
    *x = (*x) * --(*y);
}
int main ( )
{
    int number = 30;
    square(&number, &number);
    cout << number;
    return 0;
}
  • a)
    870
  • b)
    30
  • c)
    Error
  • d)
    Segmentation fault
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
What will be the output of the following C++ code?#include <iostrea...
Explanation:
- Function square:
- This function takes two integer pointers as parameters.
- It multiplies the value pointed to by the first pointer by the result of decrementing the value pointed to by the second pointer.
- Main function:
- Declares an integer variable 'number' and initializes it to 30.
- Calls the square function with the address of 'number' twice.
- The square function modifies the value of 'number' each time it is called.
- First Call:
- *x = 30 * (30-1) = 870
- After the first call, 'number' becomes 870.
- Output:
- The final value of 'number' after both calls to the square function is 870.
- Therefore, the output of the code will be 870.
Free Test
Community Answer
What will be the output of the following C++ code?#include <iostrea...
As we are passing value by reference therefore the change in the value is reflected back to the passed variable number hence value of number is changed to 870.
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What will be the output of the following C++ code?#include <iostream>using namespace std;void square (int *x, int *y){ *x = (*x) * --(*y);}int main ( ){ int number = 30; square(&number, &number); cout << number; return 0;}a)870b)30c)Errord)Segmentation faultCorrect answer is option 'A'. Can you explain this answer?
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