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What is the probability of having at least one six from 3 throws of a perfect die?
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What is the probability of having at least one six from 3 throws of a ...
Probability of getting at least one six from 3 throws of a die


To calculate the probability of getting at least one six from three throws of a perfect die, we need to consider the following:


Step 1: Find the probability of not getting a six on one throw


Since we are looking for the probability of getting at least one six, we need to find the probability of not getting a six on one throw. This can be calculated as:


Probability of not getting a six = 5/6 (since there are 5 numbers other than six on the die)


Step 2: Find the probability of not getting a six on all three throws


The probability of not getting a six on all three throws can be calculated as:


Probability of not getting a six on all three throws = (5/6) x (5/6) x (5/6) = 125/216


Step 3: Find the probability of getting at least one six


To find the probability of getting at least one six, we need to subtract the probability of not getting a six on all three throws from 1 (since the probability of getting at least one six is the complement of not getting a six on all three throws). This can be calculated as:


Probability of getting at least one six = 1 - (125/216) = 91/216


Conclusion


Therefore, the probability of getting at least one six from three throws of a perfect die is 91/216 or approximately 0.4213.
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What is the probability of having at least one six from 3 throws of a perfect die?
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