Class 6 Exam > Class 6 Questions > void *memcpy(void *dest, const void *src, siz...
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void *memcpy(void *dest, const void *src, size_t n) What does the following code do?
- a)copies n characters from src to dest
- b)copies n character from dest to src
- c)transform n character from dest to src
- d)transform n character from src to dest
Correct answer is option 'A'. Can you explain this answer?
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void *memcpy(void *dest, const void *src, size_t n) What does the foll...
Understanding memcpy Function
The `memcpy` function is a standard library function in C used for copying memory blocks.
Function Signature
c
void *memcpy(void *dest, const void *src, size_t n)
- Parameters:
- `dest`: Pointer to the destination memory where content will be copied.
- `src`: Pointer to the source memory from where content will be copied.
- `n`: Number of bytes to copy from source to destination.
What the Code Does
- The correct answer is Option A: copies n characters from src to dest.
Detailed Explanation
- Copying Process:
- The function takes `n` bytes from the memory location pointed to by `src` and copies them to the memory location pointed to by `dest`.
- Memory Overlap:
- This function does not handle overlapping memory areas safely. If `dest` and `src` overlap, the behavior is undefined. It’s important to ensure they do not point to the same location.
- Return Value:
- The function returns a pointer to the destination (`dest`), allowing for chaining of operations.
Use Cases
- Used in scenarios where raw memory needs to be manipulated, such as:
- Copying arrays.
- Handling binary data.
- Implementing buffer manipulation.
In conclusion, `memcpy` is primarily used for quickly and efficiently copying a specified number of bytes from one memory location to another, making option A the correct choice.
The `memcpy` function is a standard library function in C used for copying memory blocks.
Function Signature
c
void *memcpy(void *dest, const void *src, size_t n)
- Parameters:
- `dest`: Pointer to the destination memory where content will be copied.
- `src`: Pointer to the source memory from where content will be copied.
- `n`: Number of bytes to copy from source to destination.
What the Code Does
- The correct answer is Option A: copies n characters from src to dest.
Detailed Explanation
- Copying Process:
- The function takes `n` bytes from the memory location pointed to by `src` and copies them to the memory location pointed to by `dest`.
- Memory Overlap:
- This function does not handle overlapping memory areas safely. If `dest` and `src` overlap, the behavior is undefined. It’s important to ensure they do not point to the same location.
- Return Value:
- The function returns a pointer to the destination (`dest`), allowing for chaining of operations.
Use Cases
- Used in scenarios where raw memory needs to be manipulated, such as:
- Copying arrays.
- Handling binary data.
- Implementing buffer manipulation.
In conclusion, `memcpy` is primarily used for quickly and efficiently copying a specified number of bytes from one memory location to another, making option A the correct choice.
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Community Answer
void *memcpy(void *dest, const void *src, size_t n) What does the foll...
In the C library function memcpy() is used to copy n characters from memory area src to memory area dest.
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void *memcpy(void *dest, const void *src, size_t n) What does the following code do?a)copies n characters from src to destb)copies n character from dest to srcc)transform n character from dest to srcd)transform n character from src to destCorrect answer is option 'A'. Can you explain this answer?
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