What is the prototype of strcoll() function?a)int strcoll(const char *s1,const char *s2)b)int strcoll(const char *s1)c)int strcoll(const *s1,const *s2)d)int strcoll(const *s1)Correct answer is option 'A'. Can you explain this answer?

Question

Answer

Prototype of strcoll() function:
The prototype of the strcoll() function is:
a) int strcoll(const char *s1, const char *s2)

Explanation:
The strcoll() function is used to compare two strings based on the current locale. It compares the strings s1 and s2 and returns an integer value indicating the ordering of the strings.

Let's break down the prototype of the strcoll() function:

1. Return Type: The return type of the strcoll() function is 'int', which represents an integer value indicating the ordering of the strings.

2. Parameters: The strcoll() function takes two parameters:
- s1: It is a pointer to the first string to be compared.
- s2: It is a pointer to the second string to be compared.

Both s1 and s2 are of type 'const char *', which means they are constant pointers to characters. This implies that the function does not modify the contents of the strings.

The strcoll() function compares the strings s1 and s2 by considering the current locale. It takes into account the language-specific collation rules, which define the sorting order of characters in different languages. The function returns an integer value that indicates the ordering of the strings based on the collation rules.

The return value of the strcoll() function can have three possible meanings:
- If the return value is less than 0, it means s1 is less than s2.
- If the return value is greater than 0, it means s1 is greater than s2.
- If the return value is 0, it means s1 is equal to s2.

The strcoll() function is useful when sorting strings in a locale-specific manner, where the sorting order may differ based on the language or cultural conventions.

Answer

The prototype of strcoll() function is int strcoll(const char *s1,const char *s2).

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