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There are two containers P and Q. P contains 56 kg of salt and Q contains 36 kg of sugar. From P 24 kg of salt is taken out and poured into Q. Then 20kg of the mixture from Q is taken out and poured into P. Find the ratio of final quantity of salt to sugar in container P.
  • a)
    5/3
  • b)
    8/3
  • c)
    4/3
  • d)
    10/3
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
There are two containers P and Q. P contains 56 kg of salt and Q conta...
Initially, the Amount of sugar in Q = 36kg
Now, 24kg of salt is poured in Q,
Total quantity in Q becomes = 36kg (sugar) + 24kg (salt) = 60kg (mixture)
The ratio of salt to sugar in Q becomes = 24 : 36 = 2 : 3
Now, the Amount of salt in P = 56 - 24 = 32 kg
Again, 20kg of the mixture is taken out from Q and poured into P
Therefore, quantity of salt and sugar in P becomes = [32 + 20 * (2/5)] kg of salt + 20 * (3/5) kg of sugar = (32 + 8) kg of salt + 12 kg of sugar = 40 kg of salt + 12 kg of sugar Required ratio = (40/12) = (10/3)
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Community Answer
There are two containers P and Q. P contains 56 kg of salt and Q conta...
Initial Quantities
- Container P: 56 kg of salt
- Container Q: 36 kg of sugar
Step 1: Transfer Salt from P to Q
- 24 kg of salt is taken from P and added to Q.
New quantities:
- Container P: 56 kg - 24 kg = 32 kg of salt
- Container Q: 36 kg + 24 kg = 60 kg of mixture (36 kg sugar + 24 kg salt)
Step 2: Composition of Mixture in Q
- Total weight of mixture in Q: 60 kg
- Composition:
- Salt: 24 kg
- Sugar: 36 kg
Ratio of salt to total mixture in Q = 24/60 = 2/5
Step 3: Transfer Mixture from Q to P
- 20 kg of the mixture is taken from Q and poured into P.
- Amount of salt in 20 kg:
Salt in 20 kg = 20 kg * (2/5) = 8 kg
- Amount of sugar in 20 kg:
Sugar in 20 kg = 20 kg * (3/5) = 12 kg
Final Quantities in Container P
- Initial salt in P: 32 kg
- Salt from Q: 8 kg
- Total salt in P: 32 kg + 8 kg = 40 kg
- Sugar in P: 0 kg (initially no sugar)
- Sugar from Q: 12 kg
- Total sugar in P: 0 kg + 12 kg = 12 kg
Final Ratio of Salt to Sugar in P
- Ratio = Salt : Sugar = 40 kg : 12 kg
- Simplifying gives us:
- 40/12 = 10/3
Conclusion
- The final ratio of salt to sugar in container P is 10:3, which corresponds to option 'D'.
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There are two containers P and Q. P contains 56 kg of salt and Q contains 36 kg of sugar. From P 24 kg of salt is taken out and poured into Q. Then 20kg of the mixture from Q is taken out and poured into P. Find the ratio of final quantity of salt to sugar in container P.a)5/3b)8/3c)4/3d)10/3Correct answer is option 'D'. Can you explain this answer?
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There are two containers P and Q. P contains 56 kg of salt and Q contains 36 kg of sugar. From P 24 kg of salt is taken out and poured into Q. Then 20kg of the mixture from Q is taken out and poured into P. Find the ratio of final quantity of salt to sugar in container P.a)5/3b)8/3c)4/3d)10/3Correct answer is option 'D'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about There are two containers P and Q. P contains 56 kg of salt and Q contains 36 kg of sugar. From P 24 kg of salt is taken out and poured into Q. Then 20kg of the mixture from Q is taken out and poured into P. Find the ratio of final quantity of salt to sugar in container P.a)5/3b)8/3c)4/3d)10/3Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for There are two containers P and Q. P contains 56 kg of salt and Q contains 36 kg of sugar. From P 24 kg of salt is taken out and poured into Q. Then 20kg of the mixture from Q is taken out and poured into P. Find the ratio of final quantity of salt to sugar in container P.a)5/3b)8/3c)4/3d)10/3Correct answer is option 'D'. Can you explain this answer?.
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